Answer:
Option A is correct.
y = 35.4 bushels per acre when rainfall = 7.1 inches
Step-by-step explanation:
An image of the steps to obtain the equation that relates x to y is attached to this answer.
n = number of variables = 9
μₓ = mean of variable x (rainfall in inches)
μᵧ = mean of variable y (yield in bushels per acre)
σₓ = standard deviation of variable x (rainfall in inches)
σᵧ = standard deviation of variable y (yield in bushels per acre)
y = 4.379x + 4.268
when x = 7.1
y = 4.379(7.1) + 4.268 = 35.3589 = 35.4 bushels per acre.
Answer:
(i) ∠ABH = 14.5°
(ii) The length of AH = 4.6 m
Step-by-step explanation:
To solve the problem, we will follow the steps below;
(i)Finding ∠ABH
first lets find <HBC
<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)
46° + <HBC + 90 = 180°
<HBC+ 136° = 180°
subtract 136 from both-side of the equation
<HBC+ 136° - 136° = 180° -136°
<HBC = 44°
lets find <ABC
To do that, we need to first find <BAC
Using the sine rule
= 
A = ?
a=6.9
C=90
c=13.2
= 
sin A = 6.9 sin 90 /13.2
sinA = 0.522727
A = sin⁻¹ ( 0.522727)
A ≈ 31.5 °
<BAC = 31.5°
<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)
31.5° +<ABC + 90° = 180°
<ABC + 121.5° = 180°
subtract 121.5° from both-side of the equation
<ABC + 121.5° - 121.5° = 180° - 121.5°
<ABC = 58.5°
<ABH = <ABC - <HBC
=58.5° - 44°
=14.5°
∠ABH = 14.5°
(ii) Finding the length of AH
To find length AH, we need to first find ∠AHB
<AHB + <BHC = 180° ( angle on a straight line)
<AHB + 46° = 180°
subtract 46° from both-side of the equation
<AHB + 46°- 46° = 180° - 46°
<AHB = 134°
Using sine rule,
= 
AH = 13.2 sin 14.5 / sin 134
AH≈4.6 m
length AH = 4.6 m
The first one is your answer because if you plug into the cal it shows the x and y table and it shows that the first one is correct.
Step-by-step explanation:
Keep quit when they a teaching you and stay with participanting people/friends
Answers:
- Incorrect
- Correct
- Correct
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Explanation:
When applying any kind of reflections, the parallel sides will stay parallel. Check out the diagram below for an example of this.
So PQ stays parallel to RS. Also, QR stays parallel to PS.
The statement "PQ is parallel to PS" is incorrect because the two segments intersect at point P. This letter "P" is found in "PQ" and "PS" to show the common point of intersection. Parallel lines never intersect.
