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3 years ago

I need help with this

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

it would be C.

Step-by-step explanation:

Solve the equation for x by finding a , b , and c of the quadratic then applying the quadratic formula.

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A box contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that

Igoryamba

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

$P(A\cap B)=P(A).P(B)$

Now, According to question , we can get that

$P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}$

So,

$P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}$

So, by using the conditional probability , which state that

$P(B\mid A)=\frac{P(A\cap B)}{P(A)}$

$P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}$

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

4 0

4 years ago

Helppppppp!! Asappp!!!

neonofarm [45]

Answer:

Step-by-step explanation:

It would be 13 because you would square the 5 and 12 to get 25 + 144 which equals 169. Then you would take the square root of 169 which is 13. Hope this helps! :)

3 0

3 years ago

Simplify (−7.5)(5)(6.2).

snow_lady [41]

Answer:

-232.5

is the answer

5 0

3 years ago

I tried and now i need help

Svetradugi [14.3K]

I'm guessing the answer is B? I tried to isolate r and I got that result. Sorry if it's wrong!

3 0

3 years ago

X-8-3X-10<br> Use distributive property

icang [17]

Answer:

5x-10

Step-by-step explanation:

8x-3x-10

first you subtract 3from 8 and get 5 just add the x so your left with 10

8 0

3 years ago

Read 2 more answers

I need help with this ​

I need help with this