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Stolb23 [73]
3 years ago
6

Pls help i cant find​

Mathematics
2 answers:
Tema [17]3 years ago
6 0

Answer:

A

Step-by-step explanation:

The difference between the values of y are constant, that is

17 - 13 = 13 - 9 = 9 - 5 = 4

This indicates the relationship is linear.

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 7, 5) and (x₂, y₂ ) = (- 5, 9) ← 2 ordered pairs from the table

m = \frac{9-5}{-5+7} = \frac{4}{2} = 2

Use any ordered pair from the table for (a, b)

Using (a, b) = (- 7, 5), then

y - 5 = 2(x - (- (- 7)) , that is

y - 5 = 2(x + 7) → A

MAXImum [283]3 years ago
5 0

Answer:

Let's see the first two points: (-7, 5) and (-5, 9)

The line passes these points has a form of: y = Mx + b

=> 5 = (-7)M + b

   9 = (-5)M + b

Subtract the 1st equation from 2nd equation, we have:

4 = 2M

=> M = 2

Substitute M back into 1st equation:

=> 5 = (-7)*2 + b

=> b = 19

=> y = 2x + 19

or y - 5 = 2x + 14

or y - 5 = 2(x + 7)

=> Option A is correct

Hope this helps!

:)

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3 years ago
Aba's dog was 5 1/2 inches tall when it was a puppy but is now 14 inches tall. Aba's dog grew n-inches.
tino4ka555 [31]

Answer:

8.5 inches

Step-by-step explanation:

To find the height of Aba's dog -

Subtract 5 1/2 from 14 to find the amount she grew:

The result should be 8.5 or 8 1/2.

So Aba's dog grew 8.5 inches.

4 0
2 years ago
The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 50 ft². Find the dimensions
Mariulka [41]

Answer

Length = 10 ft

Width = 5 ft

Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

So this means the length of the rectangle will be 3x - 5

What to find:

The dimensions of the rectangle.

Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}

The quadratic equation can now be solve using factorization method:

\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}

Since the dimension can not be negative, hence the value of x will be = 5.

Therefore, the dimensions of the rectangle will be:

\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\  \\ Width=x=5\text{ }ft \end{gathered}

7 0
1 year ago
FInd the value of C.
My name is Ann [436]

Answer:

The side C equals to 10. hence the answer is letter A

Step-by-step explanation:

To solve this, we need to use trigonometric functions.

we know that sin (α) = Lo / H for a triangle. Being Lo : Length of the opposite side and H: Length of the hypotenuse.

Given α= 45º and Lo= 5√2 and replacing in the equation:

sin (45º) = 5√2 / C (1)

Using trigonometric identities we know that sin(45º) =(√2)/2. Replacing in equation (1):

sin (45º) = (√2)/2 = 5√2 / C ⇒ C = 2 *5 *√2 / (√2) ⇒ C=10

6 0
3 years ago
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