Answer: Yes
Step-by-step explanation:
First you must make use of the exponential equation that gives you the problem, there you will define that for t = 0 you are in the first week. Therefore, there you have $ 16.3 million. For the sixth week you are at t = 5 and there you must evaluate the exponential equation for that time value (t = 5). The result will be the sale of tickets for the sixth week. The procedure is attached.
The probability that the value of p(x) is greater than 315 is 0.063754
<h3>How to determine the probability that the value of p(x) is greater than 315?</h3>
From the question, the given parameters about the distribution are
- Mean value of the set of data = 283
- Standard deviation value of the set of data = 21
- The actual data value = 315
The z-score of the data value is calculated using the following formula
z = (x - mean value)/standard deviation
Substitute the given parameters in the above equation
z = (315 - 283)/21
Evaluate the difference of 315 and 283
z = 32/21
Evaluate the quotient of 32 and 21
z = 1.524
The probability that the value of p(x) is greater than 315 is then calculated as:
P(x > 315) = P(z > 1.524)
From the z table of probabilities, we have;
P(x > 315) = 0.063754
Hence, the probability that the value of p(x) is greater than 315 is 0.063754
Read more about probability at:
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Newton's law of cooling is
k (t₁ - t₂) = -ln (T₁ - T∞ / T₂ - T<span>∞)
Use the two data points in the given to find k.
t = 0, T = 154
t = 10, T = 133
Solution:
k(0 - 10) = - ln (154 - 71/ 133 - 71)
-10k = -0.291716
k = 0.02917 or 0.0292
So now find t when T = 100
0.2917 * ( 0 - t) = -ln (154 - 71 / 100 -71)
- 0.02917t = - 1.0515
t = 36. 05 minutes
to the nearest minute t = 36</span>
Answer: Part B is D. Account 4, Part C is D. Accounts 1, 3, and 5.
