Answer:−3+3=−4
2+3−=15
4−3−=19
2 3
Step 1: Pair the equations to eliminate y because the y terms are already additive inverses
1
−3+3=−4
2+3−=15
2
2+3−=15
4−3−=19
2 3 4
3 =11
5
6 −2=34
Step 2: Write the two new equations
as a system
Step 3: Substitute the value for x and z
into one of the original equations
3 =11
3 5 +2=11
4
5−3+3 −2 =−4
15+2=11
5
6 −2=34
5−3−6=−4
−3−1=−4
9x
2=−4
=−2
= 45
x = 5
−3=−3
=1
The solution (5, 1, -2)
Step-by-step explanation:
SinC=(8/17)
solve for C = arcsin(8/17)
Answer:
f(5) = 17
Step-by-step explanation:
You just plug in 5 for x:
f(5) = 3(5) + 2
f(5) = 15 +2
f(5) = 17
Hope this helps!
Refer to the figure shown below.
We shall review each of the three given measurements and decide what type of triangle we have.
Measurement a.
a=3, b=4, c=5.
For a right triangle, c² = a² + b² (Pythagorean theorem)
a² + b² = 3² + 4² = 9 + 16 = 25
c² = 5² = 25
Answer:
This is a right triangle, because c² = a² + b².
Measurement b.
a=5, b=6, c=7.
For an acute triangle, c² < a² + b².
a² + b² = 5² + 6² = 25 + 36 = 61
c² = 7² = 49
Answer:
This is an acute triangle, because c² < a² + b².
Measurement c.
a=8, b=9, c=12.
For an obtuse triangle, c² > a² + b².
a² + b² = 8² + 9² = 64 + 81 = 145
c² = 12² = 144
Answer:
This is an acute triangle because c² < a² + b².