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Westkost [7]
3 years ago
9

Assume the following is a right triangle. What is the length of the missing side?

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer:

B 53.3

Step-by-step explanation:

Looked it up with the formula.

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Someone help me with this
DaniilM [7]

Answer: 7.5

Step-by-step explanation:

3 0
3 years ago
5. The students are trying to determine the distance between two particular
natali 33 [55]

Answer:

The actual distance between the cities is 211.67 cm.

Step-by-step explanation:

Given:

The map key indicates that 4.5 cm is equivalent to 75 cm.

Now, to find the actual distance between the cities if the cities are 12.7 cm apart on the map.

Let the actual distance be x.

So, we set a proportion to find the actual distance:

4.5:12.7 = 75:x.

<em>Changing into fractions.</em>

\frac{4.5}{12.7} =\frac{75}{x}

<em>By cross multiplication we get:</em>

4.5x=952.5

<em>Dividing both sides by 4.5 we get:</em>

x=211.67

Therefore, the actual distance between the cities is 211.67 cm.

8 0
3 years ago
This is the last time its happened twice please i need the answer
slamgirl [31]

Answer:

I think the answer is F hope its right fingers crossed!

Step-by-step explanation:

3 0
3 years ago
–2.5 + (–3.5) Which number line shows the sum? (and i know its not -6)
Leto [7]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
EASY BRAINLIEST PLEASE HELP!!
butalik [34]

Answer:

see below

Step-by-step explanation:

<h3>Proposition:</h3>

Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE

<h3>Proof:</h3>

1)The lines AD and BC are parallel and AC their transversal therefore,

\displaystyle  \angle DAC =  \angle ACB \\  \ \qquad [\text{ alternate angles theorem}]

2)The lines AB and DC are parallel and BD their transversal therefore,

\displaystyle  \angle BD C=  \angle ABD \\  \ \qquad [\text{ alternate angles theorem}]

3)now in triangle ∆AEB and ∆CED

  • \displaystyle \angle EAD=\angle ECB
  • \angle EDA=\angle EBC
  • \displaystyle AD=BC

therefore,

\displaystyle  \Delta AEB  \cong  \Delta CED

hence,

  • AE=CE
  • DE=BE

Proven

6 0
3 years ago
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