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2 years ago

Assume the following is a right triangle. What is the length of the missing side?

Mathematics

1 answer:

almond37 [142]2 years ago

3 0

Answer:

B 53.3

Step-by-step explanation:

Looked it up with the formula.

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A stock can go up, go down, or stay unchanged. How many possibilities are there if you own 3 stocks?

Gala2k [10]

Answer:

There are 27 different possible outcomes.

Step-by-step explanation:

Assuming that you have 3 different stocks:

First, we need to find the number of events and the number of possible outcomes for each event.

Here we can assume that each one of the stocks is a event, and the number of possible outcomes for each one are:

Stock 1: 3 options (up, down, stay)

Stock 2: 3 options (up, down, stay)

Stock 3: 3 options (up, down, stay)

The total number of possible outcomes is equal to the product of the numbers of options for all the events.

Then the total number of possibilities is:

C = 3*3*3 = 27

4 0

2 years ago

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

2 years ago

CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU.

tiny-mole [99]

Answer:

six and one over twelve

Step-by-step explanation:

1/4 + 5 5/6=1/4+35/6 = 6 1/12

8 0

2 years ago

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Heyyyyyy , Can you please help me with this

erik [133]

Answer:

19 houses

Step-by-step explanation:

90*(2/5)=36

90-36=54

54*(2/3)=37

54-37=19

8 0

2 years ago

Which expression is equivalent to 4 * 4 * 4 * 5 * 5?

jekas [21]

Answer:

the closests if 43 multiply by 25

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers