$g(x)=\dfrac{1}{2}(x-3)+1\\\\y=\dfrac{1}{2}(x-3)+1\\\\\text{replace x with y and y with x}\\\\x=\dfrac{1}{2}(y-3)+1\\\\\text{solve for y}\\\\\dfrac{1}{2}(y-3)+1=x\ \ \ \ |-1\\\\\dfrac{1}{2}(y-3)=x-1\ \ \ \ |\cdot2\\\\y-3=2x-2\ \ \ \ |+3\\\\y=2x+1\\\\Answer:\ \boxed{g^{-1}(x)=2x+1}$

4 0

3 years ago

Brock heard that as a general rule, he should spend no more than one week's pay on rent. If Brock's salary is $25,200 per year,

olasank [31]

There are about 52 weeks in a year, so divide 25200 by 52 (484.6). He gets paid $484.60 per week. So he should spend a maximum of C. $485 on rent per month.

8 0

3 years ago

Read 2 more answers

A child has a box of candies which might have a toy inside . The odds against the box having toys are 17/2 . What is the probabi

Elden [556K]

17/2 = probability is low

4 0

4 years ago