I think you're missing a bit of the question. If her savings can be modeled by x...?
Answer:
The least number of meals Amelia needs to cater in order to begin making profit = 38 meals.
Step-by-step explanation:
Given - Amelia runs a catering business. Based on her records, her weekly
profit can be modeled by P= -2x² + 152x - 150, where x is the
number of meals she caters and P is her profit. When P is negative,
Amelia losses money.
To find - What is the least number of meals Amelia needs to cater in order
to begin making profit.
Proof -
As given, P = -2x² + 152x - 150
Now,
Above the break-even point, she only get profit
The break -even point is a point where there is no profit, and no loss.
Now,
For break-even point,
⇒
⇒-4x + 152 = 0
⇒- 4x = - 152
⇒4x = 152
⇒x = = 38
∴ we get
If Amelia caters at least 38 meals , then she makes Profit.
I believe that the amount of mugs he has used is 2 because you need 4/10 which is equivalent to 2 mugs
Answer:
C
Step-by-step explanation:
The graphs are reflected across the y-axis.
Y= -3/2x
Because of rise over run so the rise is positive three and the run is negative 2 since it goes towards the negative direction