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2 years ago

14

If the square section of the auditorium has a side of 15 metres and the length of the rectangle is three times the length of the

sides. Calculate the perimeter of the entire auditorium.

1 answer:

lianna [129]2 years ago

4 0

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Peyton has collected 120 aluminum cans for recycling. If 20 cans will fit in each blue plastic bag, how many bags will she need

gogolik [260]

Hi Renee!

--------------------------------------------

We Know:

120 aluminum cans.

20 cans fit in each blue bag.

--------------------------------------------

Solution:

120 / 20 = 6

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Answer:

She will need 6 bags to carry all the aluminum cans.

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Hope This Helps :)

6 0

3 years ago

1. Find 3 equivalent fraction for the following: a) 5/6 b) 7/11 c) 9/7

SOVA2 [1]

Answer:

Step-by-step explanation:

To find equivalent fractions, multiply the numerator and the denominator by the same table.

a) 5/6

$\frac{5*2}{6*2}=\frac{10}{12}\\\\\frac{5*3}{6*3}=\frac{15}{18}\\\\\frac{5*4}{6*4}=\frac{20}{24}$

b) 7/11

$\frac{7*3}{11*3}=\frac{21}{33}\\\\\frac{7*4}{11*4}=\frac{28}{44}\\\\\frac{7*5}{11*5}=\frac{35}{55}$

c)9/7

$\frac{9*2}{7*2}=\frac{18}{14}\\\\\frac{9*5}{7*5}=\frac{45}{35}\\\\\frac{9*10}{7*10}=\frac{90}{70}$

8 0

3 years ago

Please help been stuck on this for 40 minutes

choli [55]

we have given y interms of x.

we have given that add 2 to x.

which means $y=x+2$

so we have $x=2 ,y=x+2=2+2=4$ .

so when x $=2 ,y=4$ .

$x=4,y=x+4=4+2=6.$ .

$y=x+2,y=6+2=8$ .

3 0

3 years ago

Read 2 more answers

Haley makes earrings and packages them into cube boxes that measure 1/6 foot wide. how many 1/6 foot cubic boxes can she fit int

navik [9.2K]

Answer: $28\ cubes$

Step-by-step explanation:

The volume of a cube can be found with this formula:

$V_{(c)}=s^3$

Where "s" is the lenght of any edge of the cube.

The formula for calculate the volume of a rectangular prism is:

$V_{rp}=lwh$

Where "l" is the lenght, "w" is the width and "h" is the height.

We need to find the volume of a cube box:

$V_1=s^3=(\frac{1}{6}ft)^3=\frac{1}{216}ft^3$

To find the volume of the shipping box, first we must convert the mixed number to an improper fraction:

$1\frac{1}{6}=\frac{(6*1)+1}{6}=\frac{7}{6}$

Then the volume of the shipping box is:

$V_2=lwh\\\\V_2=(\frac{7}{6}ft)(\frac{1}{3}ft)(\frac{1}{3}ft)=\frac{7}{54}ft^3$

Now, in order to find the number of cube boxes can Haley fits into a shipping box, you must divide the the volume of the shipping box by the volume of one cube. This is:

$\frac{\frac{7}{54}ft^3}{\frac{1}{216}ft^3}=28$

6 0

3 years ago

Graph the function and analyze it for domain, range, continuity, increasing or decreaseing behavior, symmetry, boundedness, extr

Sunny_sXe [5.5K]

Answer:

$f(x) = 3 \cdot 0.2^x$

Step-by-step explanation:

$f(x) = 3 \cdot 0.2^x$

Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is $\mathbb{R}$

Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore $(0, \infty)$ .

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe $f(x-1) > f(x)$ for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies $f(x) < 0$ .

Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)

Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: $y=0$ .

End behaviour: As $x \rightarrow \infty, f(x) \rightarrow 0$ . As $x \rightarrow -\infty, f(x) \rightarrow +\infty$

5 0

3 years ago