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3 years ago

Mention 10 forest trees and their botanical names with their uses

Biology

2 answers:

mafiozo [28]3 years ago

5 0

Answer:

Explanation:

California Box Elder- Acer negundo californicum

Japanese Maple- Acer palmatum

Silk Tree- Albizia julibrissin

Strawberry tree- Arbutus unedo

Bird of paradise shrub- Caesalpinia gilliesii

Harlequin Glorybower- Clerodendrum trichotomum

Cypress- Cupressus spec.

Oregon Ash- Fraxinus latifolia

Sweet Bay- Laurus nobilis 'Saratoga'

inessss [21]3 years ago

5 0

Explanation:

<h3> Thank you </h3>

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Recall that the biological species concept defines a species as a group of populations whose members have the potential to inter

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Population 1: A, D, F, H, I, & K

Population 2: B, E, L

Population 3: C, G, J

In here even though populations are separated by large distances ( an example is A & K) they can still be connected through gene flow.

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3 years ago

What food chain is there from the movie Finding Nemo?

Katarina [22]

There are four different examples of food chains in the movie "Finding Nemo".
1) Whales Eat Krill
2) Sharks eat smaller fish
3) Gulls (birds) eat anything they can
4) Humans (fishermen) eat fish (implied through the harvesting or attempted harvesting of fish scene)
5) Crabs scavenging for food from/along the pipes on the ocean floor
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3 years ago

The average human body contains 6.10 L of blood with a Fe2+ concentration of 1.50×10−5 M . If a person ingests 12.0 mL of 14.0 m

Crank

Answer: The percentage of iron(II) in the blood sequestered by the cyanide ion is 18.4%

Explanation:

Having the reaction NaCN(ac) + Fe2+ ⇒ CNFe + Na+ ; you could follow this procedure:

1. Find the number of moles of Fe2+ in the 6.10L of blood and the number of moles of CN- in the 0.012L (0.012L=12mL) solution.

First, notice that the amount of CN- moles in the 12mL solution is the same as if we were looking for the amount of moles NaCN in the solution. This is because most sodium salts dissociate completely in aqueous solution.

Then having the Molar concentrations of both CN- and Fe2+:

Fe2+ concentration = 1.5x $10^{-5}$ M = 1.5x $10^{-5}$ moles (n)/L

Moles de Fe2+ en 6.01L= (1.5x $10^{-5}$ moles (n)/L)*6.01L= 9.15x $10^{-5}$ moles

NaCN or CN- concentration = 14mM=0,0014M=(0,0014n/L)

Moles de CN- en 0,012L= (0,0014n/L)*0,012L= 1.68x $10^{-5}$ moles

2. Understand how many moles of Fe2+ are sequestered by CN- :

Beacause 1 mol of CN- react (sequester) with 1 mol of Fe2+ to form 1 mol of CNFe, then 1.68x $10^{-5}$ moles of CN- is going to sequester 1.68x $10^{-5}$ moles of Fe2+ to form 1.68x $10^{-5}$ moles of CNFe.

3. Calculate the percentage of Fe2+ sequestered:

% Fe2+ = (moles of Fe2+ sequestered/Total moles of Fe2+ in the blood)*100

⇒ % Fe2+ = (1.68x $10^{-5}$ ) / (9.15x $10^{-5}$ )=0.184*100 = 18.4% Percentage of Fe2+ moles sequestered by cyanide ion (CN-).

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3 years ago

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3 years ago

Mention 10 forest trees and their botanical names with their uses​

Mention 10 forest trees and their botanical names with their uses