1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tia_tia [17]
3 years ago
5

When creating loyal customers you must develop all of the following except: a. Smooth relationships b.customer marketing c. Dedi

cated employees d. Memorable services
Computers and Technology
2 answers:
Softa [21]3 years ago
8 0
Most likely c since it’s customer marketing
bixtya [17]3 years ago
7 0

Answer: I think a

Explanation: sorry I’m in wrong, have a great day!! :D

You might be interested in
Which binary number is equivalent to the decimal number 104?
ra1l [238]

B. 01101000

For future reference you can look up decimal to binary calculators online; or binary to decimal.

6 0
3 years ago
How do I get my text box to stop moving continuously on a Chromebook?
pickupchik [31]

Answer:

Go to Settings. Click on Advanced Settings. Scroll down to the Accessibility section. Make sure that the box next to “Automatically click when the mouse pointer stops” is Unchecked.

Explanation:

here you go hope this helps!!

5 0
3 years ago
Read 2 more answers
An online museum is creating a site hosting hundreds of thousands of digital representations of art from around the world. The w
Firdavs [7]

Answer:

A. the museum can choose a heuristic approach which will achieve a lossless compression, but they cannot be sure that it is the most efficient compression for each image

C. algorithms for lossless compression exist, so the museum can use those to compress the image

Explanation:

4 0
3 years ago
Which of the following remote access security technologies performs authentication through a three-way handshake (that is, chall
levacccp [35]

Answer:

CHAP

Explanation:

CHAP allows a client to be authenticated without sending credential information across a network.

7 0
3 years ago
Create a Binary Expressions Tree Class and create a menu driven programyour program should be able to read multiple expressions
solong [7]

Answer:

Explanation:

Program:

#include<iostream>

#include <bits/stdc++.h>

using namespace std;

//check for operator

bool isOperator(char c)

{

switch(c)

{

case '+': case '-': case '/': case '*': case '^':

return true;

}

return false;

}

//Converter class

class Converter

{

private:

string str;

public:

//constructor

Converter(string s):str(s){}

//convert from infix to postfix expression

string toPostFix(string str)

{

stack <char> as;

int i, pre1, pre2;

string result="";

as.push('(');

str = str + ")";

for (i = 0; i < str.size(); i++)

{

char ch = str[i];

if(ch==' ') continue;

if (ch == '(')

as.push(ch);

else if (ch == ')')

{

while (as.size() != 0 && as.top() != '('){

result = result + as.top() + " ";

as.pop();

}

as.pop();

}

else if(isOperator(ch))

{

while (as.size() != 0 && as.top() != '(')

{

pre1 = precedence(ch);

pre2 = precedence(as.top());

if (pre2 >= pre1){

result = result + as.top() + " ";

as.pop();

}

else break;

}

as.push(ch);

}

else

{

result = result + ch;

}

}

while(as.size() != 0 && as.top() != '(') {

result += as.top() + " ";

as.pop();

}

return result;

}

//return the precedence of an operator

int precedence(char ch)

{

int choice = 0;

switch (ch) {

case '+':

choice = 0;

break;

case '-':

choice = 0;

break;

case '*':

choice = 1;

break;

case '/':

choice = 1;

break;

case '^':

choice = 2;

default:

choice = -999;

}

return choice;

}

};

//Node class

class Node

{

public:

string element;

Node *leftChild;

Node *rightChild;

//constructors

Node (string s):element(s),leftChild(nullptr),rightChild(nullptr) {}

Node (string s, Node* l, Node* r):element(s),leftChild(l),rightChild(r) {}

};

//ExpressionTree class

class ExpressionTree

{

public:

//expression tree construction

Node* covert(string postfix)

{

stack <Node*> stk;

Node *t = nullptr;

for(int i=0; i<postfix.size(); i++)

{

if(postfix[i]==' ') continue;

string s(1, postfix[i]);

t = new Node(s);

if(!isOperator(postfix[i]))

{

stk.push(t);

}

else

{

Node *r = nullptr, *l = nullptr;

if(!stk.empty()){

r = stk.top();

stk.pop();

}

if(!stk.empty()){

l = stk.top();

stk.pop();

}

t->leftChild = l;

t->rightChild = r;

stk.push(t);

}

}

return stk.top();

}

//inorder traversal

void infix(Node *root)

{

if(root!=nullptr)

{

cout<< "(";

infix(root->leftChild);

cout<<root->element;

infix(root->rightChild);

cout<<")";

}

}

//postorder traversal

void postfix(Node *root)

{

if(root!=nullptr)

{

postfix(root->leftChild);

postfix(root->rightChild);

cout << root->element << " ";

}

}

//preorder traversal

void prefix(Node *root)

{

if(root!=nullptr)

{

cout<< root->element << " ";

prefix(root->leftChild);

prefix(root->rightChild);

}

}

};

//main method

int main()

{

string infix;

cout<<"Enter the expression: ";

cin >> infix;

Converter conv(infix);

string postfix = conv.toPostFix(infix);

cout<<"Postfix Expression: " << postfix<<endl;

if(postfix == "")

{

cout<<"Invalid expression";

return 1;

}

ExpressionTree etree;

Node *root = etree.covert(postfix);

cout<<"Infix: ";

etree.infix(root);

cout<<endl;

cout<<"Prefix: ";

etree.prefix(root);

cout<<endl;

cout<< "Postfix: ";

etree.postfix(root);

cout<<endl;

return 0;

}

3 0
3 years ago
Other questions:
  • Which of the following translates packets so that the node can understand them once they enter through a port?
    8·2 answers
  • true or false manual handling of materials accounts for the primary source of energy in the workplace
    13·2 answers
  • Explain the nature of documents that can be suitable for mergin
    12·1 answer
  • Which website allows you to host your podcast for at a cost that includes your domain name?
    9·2 answers
  • What does the following loop do?
    5·1 answer
  • HOW TO FREE UP RAM/MEMORY ON YOUR DEVICE?
    12·2 answers
  • Python: Bad input on line 8. What is the fix, please can someone tell me I’m desperate?
    10·1 answer
  • Where are methods listed in a UML class diagram showing three parts?
    8·1 answer
  • How to do GCD on small basic?​
    7·1 answer
  • I hope The characters That I want in Mortal kombat 12 is Lori and peron That’s My character wishlist in The next Mortal kombat g
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!