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Veseljchak [2.6K]

4 years ago

11

If the boundary lines of two half planes are parallel, then they have no solution area.

1 answer:

jenyasd209 [6]4 years ago

8 0

Answer: True

Step-by-step explanation:

(Guess dont take this seriously)

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write in scientific notation 1. 0.0000364 2. 0.00751 3. 0.10005 4. 1,094 5. 0.00000099 6. 0.04101 7. 10,500 8. 8,9000

solmaris [256]

$1.\\0\underbrace{.00003}_{5\to}54=3.54\times10^{-5}\\2.\\0\underbrace{.007}_{3\to}51=7.51\times10^{-3}\\3.\\0\underbrace{.1}_{1\to}0005=1.0005\times10^{-1}\\4.\\1\underbrace{,094}_{\leftarrow3}=1.094\times10^3\\5.\\0\underbrace{.0000009}_{7\to}9=9.9\times10^{-7}$
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3 0

3 years ago

An airplane on a transatlantic flight took 4 hours 20 minutes to get from New York to its destination, a distance of 3,000 miles

ankoles [38]

738.

3200/4.33= 739.01

The closest to that is 738

4 0

2 years ago

Antar is flying a triangular-shaped kite. It has a height of 4 1/2 feet and a base of 5 3/4 feet. What is the area of Antar's ki

kotykmax [81]

$Area\ of\ triangle: \\ \frac{1}{2}bh \\ \\ \frac{1}{2}(4.5\ feet)(5.75\ feet) \\ \\ \boxed{12.9375\ feet^{2}}$

8 0

3 years ago

Read 2 more answers

For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The

Tema [17]

Answer:

Number of cheaper dresses sold is 35

Number of expensive dresses sold is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of expensive dresses = $140

Total cost of the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive dress = ?

Solution:

Let

The number of cheaper dresses be x

The number of expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250

$x \times90 +y \times 140 = 5250$ = $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress = 20 + number of expensive dress

x = 20 + y---------------------------------------(1)

$(20+y) \times90 +y \times 140 = 5250 = 5250$

$(20 \times 90 +y\times 90) +y \times 140= 5250$

$1800 + 90y+ 140y = 5250$

$1800 + 230y = 5250$

$230y =5250 -1800$

$230y = 3450$

$y = \frac{3450}{230}$

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0

4 years ago

Based on a survey, assume that 38% of consumers are comfortable having drones deliver their purchases. Suppose that we

Maslowich

Answer:

$n = 4$

$x = 2$

$p = 38\%$

$q = 62\%$

Step-by-step explanation:

Required

Find n, x, p and q

n always represent the population surveyed;

So:

$n = 4$

x represents the sample from the population

So:

$x = 2$

p always represents the given proportion

$p = 38\%$

Solving for q

$p + q = 1$

$q = 1 - p$

$q = 1 - 38\%$

$q = 62\%$

5 0

3 years ago