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2 years ago

Find the circumference, giving brainlies pls asap

Mathematics

2 answers:

Amanda [17]2 years ago

5 0

its a or b, sorry im not much help

zalisa [80]2 years ago

4 0

Answer:

B) 12.6π ; 39.6

Step-by-step explanation:

Circumference:

C = 2πr

C = 2(3.14)(6.3)

C = 6.28(6.3)

C = 39.6

C = 2πr

C = 2π6.3

C = 12.6π

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write the x and y coordinate (in the second and third column, respectively) of dilation of quadrilateral ABCD with vertices A(1,

gayaneshka [121]

Answer:

The coordinates of the dillated vertices are $A'(x,y) = (2,2)$ , $B'(x,y) = (4,4)$ , $C'(x,y) = (8,2)$ and $D'(x,y) = (4,-2)$ .

Step-by-step explanation:

From Linear Algebra, we define dilation by the following equation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation, dimensionless.

$P(x,y)$ - Original point, dimensionless.

$k$ - Scale factor, dimensionless.

$P'(x,y)$ - Dilated point, dimensionless.

If we know that $O(x,y) = (0, 0)$ , $k = 2$ , $A(x,y) = (1,1)$ , $B(x,y) = (2,2)$ , $C(x,y) = (4,1)$ and $D(x,y) = (2,-1)$ , then the dilated points are, respectively:

Point A

$A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)]$ (2)

$A'(x,y) = (0,0) + 2\cdot [(1,1)-(0,0)]$

$A'(x,y) = (2,2)$

Point B

$B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)]$ (3)

$B'(x,y) = (0,0) + 2\cdot [(2,2)-(0,0)]$

$B'(x,y) = (4,4)$

Point C

$C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)]$

$C'(x,y) = (0,0) + 2\cdot [(4,1)-(0,0)]$

$C'(x,y) = (8,2)$

Point D

$D'(x,y) = O(x,y) + k\cdot [D(x,y)-O(x,y)]$

$D'(x,y) = (0,0) + 2\cdot [(2,-1)-(0,0)]$

$D'(x,y) = (4,-2)$

The coordinates of the dillated vertices are $A'(x,y) = (2,2)$ , $B'(x,y) = (4,4)$ , $C'(x,y) = (8,2)$ and $D'(x,y) = (4,-2)$ .

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2 years ago

David made a table to relate two customary units. Label the columns of the table

tigry1 [53]

The customary unit is add 16 each time hope i help

5 0

2 years ago

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Solve for x (2x-8) (9x-10)

mars1129 [50]

Answer

x+3=17

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is the answer ? ....

Alexxandr [17]

Answer:

9.) A

10.) B

Step-by-step explanation:

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7 0

2 years ago

What are the zeros of f(x) = x2 - 8x+16?

Stels [109]

Answer:

x=4

Step-by-step explanation:

f(x) = x^2 - 8x+16

Set equal to zero

0 = x^2 -8x +16

Factor

what 2 numbers multiply to 16 and add to -8

-4*-4 = 16

-4+-4 = -8

0= (x-4)(x-4)

Using the zero product property

x-4 = 0 x-4 =0

x=4 x=4

3 0

2 years ago