Answer:
1) -0.005
2) -1/2
3) 0
4) 2
now can i plz have brainliest? =)
Answer:
a) Attachment
b) 6 to 14.8 in
c) 2.5%
Step-by-step explanation:
Given:
- The mean is u = 10.4 in
- The standard deviation s.d = 4.4
- Sample size n = 28
Find:
- Choose the correct Normal model for tree diameters. A. B. C.
- What size would you expect the central 68% of all tree diameters to be?Using the 68-95-99.7 rule, the central 68% of the tree diameters are between ____ inches and _____ inches.
- About what percent of the trees should have diameters below 1.6 inches?
Solution:
- The central 68% lies within two s.d from mean.
10.4 + 1*4.4 = 14.8
10.4 - 1*4.4 = 6
Hence, the central 68% are between 6 and 14.8 inches.
- The central 95% lies within two s.d from mean.
10.4 + 2*4.4 = 19.2
10.4 - 2*4.4 = 1.6
- The central 95% are between 1.6 and 19.2 inches.
- Hence, P ( X < 1.6) = (1 - 0.95)/2 = 0.025 or 2.5%
Answer:
Step-by-step explanation:
Otah lowvely hooman lol. . .
lol give my other acc brainlist X3
Sad girl Shoyo here!!!~<3
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.