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mr_godi [17]
3 years ago
8

5. given ABC, find the value of x

Mathematics
1 answer:
Fudgin [204]3 years ago
6 0
There's no question g
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There are 24 pictures on a roll of film. Adelle had 84 pictures from her trip home. She said that 12 other pictures were spoiled
galina1969 [7]
The answer is 4.

There were in total 96 pictures (84 pictures  + 12 spoiled = 96 pictures).
1 roll of film has 24 pictures. x rolls of film have 96 pictures.
1 : 24 = x : 96
x = 1 * 96 : 24
x = 4


6 0
3 years ago
An artist is designing a kite like the one show below. Calculate the area to determine how much material she will need to create
neonofarm [45]

Answer:

The answer is 161.5

Step-by-step explanation:

Step-by-step explanation: The top half of the kite is 6 in times 17 in because 8.5 + 8.5 = 17 so its 102. Half of 102 is 51 so 51 is the area of the top half. The bottom half is 13 in times 17 in which equals 221. Half of 221 is  110.5. Then 110.5 + 51 = 161.5... So your answer is 161.5 square inches.

7 0
2 years ago
Find BC.<br> Round to the nearest tenth.<br> C<br> 12<br> A<br> 87°<br> 9<br> B
Dmitrij [34]

Answer:

C-10

A-90

B-10

Step-by-step explanation:

For rounding off to nearest tens, we compare the last digit.

5 0
1 year ago
Please help me with this math!
STALIN [3.7K]
1. Alternate exterior angles

So, C

2.
180 = 76 + 2x
104 = 2x
52 = x

So, B

4.

4a. No
4b. Yes
4c. No
4d. Yes

5.
180 = 35 + 35 + 2x
180 = 70 + 2x
110 = 2x
55 = x

So, C.

7.

12/8 = 30/y

Cross multiply

12y = 240
y = 20

So, C

8. Alternate interior angles

So, A

9.

A C and D
6 0
3 years ago
Read 2 more answers
A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a
Rashid [163]

Answer:

Length of original rectangle: 11 units.

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

\text{Perimeter of new rectangle}=20

Step-by-step explanation:

Let x represent width of the original rectangle.  

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be x+6.

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be x-2.

The length of new rectangle would be x+6-4=x+2.

The area of new rectangle would be (x+2)(x-2).

Now we will equate area of new rectangle with 21 and solve for x as:

(x+2)(x-2)=21

Applying difference of squares, we will get:

x^2-2^2=21

x^2-4=21

x^2-4+4=21+4

x^2=25

Since width cannot be negative, so we will take positive square root of both sides.

\sqrt{x^2}=\sqrt{25}

x=5

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be x+6\Rightarrow x+5=11.

Therefore, the length of original rectangle is 11 units.

\text{Area of original rectangle}=5\times 11

\text{Area of original rectangle}=55    

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

We know that perimeter of rectangle is two times the sum of length and width.

\text{Perimeter of new rectangle}=2((x+2)+(x-2))

\text{Perimeter of new rectangle}=2((5+2)+(5-2))

\text{Perimeter of new rectangle}=2(7+3)

\text{Perimeter of new rectangle}=2(10)

\text{Perimeter of new rectangle}=20

Therefore, the perimeter of the new rectangle is 20 units.

7 0
3 years ago
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