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2 years ago

Fine the area of a circle with radius 8 in.

Mathematics

1 answer:

denpristay [2]2 years ago

6 0

Answer:

around 200.96

Step-by-step explanation:

circle area = pir^2

pi*8^2

pi*64

=around 200.96

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Using the table for many repetitions of the experiment of tossing a coin 10 times, what is the mean number of heads in 50 repeti

PtichkaEL [24]

When there are 1000 repetitions, the mean will be 5.002.

The charts that you have list the number of total heads when you flip the coin 10 times in each trial.

Multiply the total of each by the number number of heads for that category and divide by 1000.

1 x 0
8 x 1
43 x 2
117 x 3
2017 x 4
248 x 5
203 x 6
121 x 7
45 x 8
6 x 9
1 x 10

If you add up those products and divide by 1000, you have 5.002.

Using the law of large numbers, the experiment with 1000 rolls will be the closest to the theoretical amount.

7 0

3 years ago

Help me with this probability question for (7th grade math)

ElenaW [278]

There is a 3/6 possibility for an even number to get chosen.

Might be wrong

bye

4 0

2 years ago

Read 2 more answers

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

2 years ago

What is the probability of rolling a 2 or a 4 on a 6 section spinner?

sergey [27]

Rolling an even number (2, 4 or 6) is an event, and rolling an odd number (1, 3 or 5) is also an event. In Experiment 1 the probability of each outcome is always the same. The probability of landing on each color of the spinner is always one fourth.

3 0

2 years ago

18+6/-4-16 HELP only d part

Ivahew [28]

Answer:

$\frac{1}{2}$ is the answer