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Helga [31]
3 years ago
9

Kym used the integer tiles to find the sum of (–3) + 6. The line showed that the answer is negative 3. Which of the following do

es Kym need to do to get the correct answer?
A.add three more negative tiles
B.remove the zero pairs
C.add three more positive tiles
D.remove three positive tiles
Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0

Answer:

remove the zero pairs

Step-by-step explanation:

just did the answer :)

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Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a
NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

And then substitute the values in it then

Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

Learn more about probability here

brainly.com/question/24756209

#SPJ4

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7 0
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If Raj randomly chooses a point in the square below, what is the probability that point is not in the circle? Assume that pi = 3
hodyreva [135]

Answer:

49.7%

Step-by-step explanation:

A cdircle is located within a square.

<u>Area of the circle</u>

Area = \pir^{2}, where r = 4 units.

Area Circle = 50.3 units^2

<u>Area of the square</u>

Area = l*w or l^2 for a square, since l = w

Area = (10 units)^2

Area = 100 units^2

<u>Area in the square but outside the circle</u>

This is the difference [Square minus Circle Areas]

Square minus Circle Areas = 100 - 50.3  or <u>49.7 units^2</u>

<u>Probability</u>

The probability of picking a point in the square that is not in the circle is the ration of the two areas:  <u>[Outside Circle/Square]x100%</u>

<u></u>

<u>(</u>49.7 units^2)/(100 units^2)x100% = 49.7%

<u></u>

6 0
1 year ago
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