Given f(x)=3x^2+kx+9, and the remainder when f(x) is divided by x-3 is 6, then what is the value of k?
1 answer:
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You can see how the difference between two consecutive terms is constantly increasing:
So, for the next terms we'll have to add +9, +11, +13 and so on.
Also, note that is obtained by adding the 2nd odd number to
,
is obtained by adding the 3rd odd number to
, and so on.
So, the recursive formula is
For the explicit formula, recall that the sum of the first n odd numbers is n squared. Taking into account the fact that we're not starting from 1, we have
Answer:
x=3 and y=1
Step-by-step explanation:
First find the deteminant
That is ad-bc
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