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user100 [1]
3 years ago
8

Can someone help me pls?

Mathematics
1 answer:
Fofino [41]3 years ago
3 0

Answer:

264

Step-by-step explanation:

took the test

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On the coldest night in North Ice, Greenland, the temperature dropped from 0°C to −21°Cin 7 hours. What is the average temperatu
Mkey [24]

Answer:

The answers -3

(I took the test)

3 0
3 years ago
Ayuda el tema en concreto es "Métodos de solución de ecuaciones simultáneas"
Mumz [18]

Answer:

<u>x = 3 y y = 2</u>

Step-by-step explanation:

a) Metodo de reduccion:

Para aplicar este metodo debemos multiplcar por 3 la ecuacion 2 y sumarlas.

4x-3y=6

5x+y=17 *3

4x-3y=6

15x+3y=51

-------sumamos las ecuacioens--------

19x=57

x=3

Ahora, remplazamos x en la ecuacion 2.

5(3)+y=17

y=2

b) Igualacion

Debemos despejar x en ambas y luego igualarlas

x=\frac{6+3y}{4}

x=\frac{17-y}{5}

Igualando:

\frac{6+3y}{4}=\frac{17-y}{5}

5(6+3y)=4(17-y)

19y=8

y=2

Ahora, remplazamos y en la ecuacion 2.

5x+2=17

5x=15

x=3

c) Sustitucion

Despejamos x de la primero ecuacion y lo remplazamos en dos.

x=\frac{6+3y}{4}

5\frac{(6+3y)}{4}+y=17

Multiplicamos por 4

5(6+3y)+4y=68

30+15y+4y=68

30+19y=68      

19y=38  

y=2  

Remplazando en 1.

4x-3(2)=6

4x-6=6

4x=12

x=3          

               

5 0
2 years ago
A force of 5 pounds stretches a spring 1 foot. A mass weighing 6.4 pounds is attached to the spring, and the system is then imme
Rudiy27

Answer:

x(t) = e ^{-3t} [-cos (4t) - \frac{3}{4}sin (4t)]

Step-by-step explanation:

A force of 5 pounds stretches a spring 1 foot.

This implies that, the string constant (K) = 5 lbs? ft

Mass (m) = \frac{6.4}{32}

= \frac{1}{5}

The damping force F_d = -1.2 v

The negativity of the damping force is due to the fact that it opposes the motion.

Then the force due to the spring is :

F_5 = -kx    

where;

x = the mass distance from the equilibrium point.

Total Force F = F_d + F_s

⇒ F = -1.2v - 5.0 x

⇒ mx = -1.2v - 5.0 x

where v = x' and a = x"

Hence, the equation becomes mx" =  -1.2x' - 5.0 x

⇒  \frac{1}{5} x"+1.2x'+5v = 0

⇒ x" +6x'+25x =0

The auxiliary equation is can be written as:

r^2 +6x+25=0

⇒ r = \frac{-6 \pm\sqrt{36-100} }{2}

r = -3\pm4i

r = -3+4i  OR   -3-4i

Now,the general equation of motion is :

x(t)=e^{-3t}(C_1cos(4t)+C_2sin(4t))

x'(t)=-3e^{-3t}(C_1cos(4t)+C_2sin(4t)) + e^{-3t}(-4C_1sin(4t)+4C_2 cos(4t))

Initial Conditions are:

x(0) = -1 and x' (0) = 0

x(0) = -1

⇒ -1 = C_1

x' (0) =0 ⇒ 0 = -3(-1) + (4C_2)

⇒ C_2 = -\frac{3}{4}

Thus:

x(t) = e ^{-3t} [-cos (4t) - \frac{3}{4}sin (4t)]

7 0
3 years ago
Plz hurry will mark brainlyest.
Ne4ueva [31]

Answer:62

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Value​ rent-a-car rental a luxury car at a daily rate of ​$43.09 plus 4 cents per mile. a business person is allotted ​$100 for
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<span>To calculate the total miles he is allowed we must setup an expression for total cost of the car per day. Cost = 43.09 + .04x where x is the number of miles driven. To find out the number of miles driven with $100, we plug in $100 for cost and solve for x. Doing this we get 100 = 43.09 + .04x, where .04x = 56.91 and solving for x we get x=1422.75 or 1422 miles. In this case we do not round up since adding an additional mile would put us over the $100 budget. Answer = 1422 miles.</span>
8 0
3 years ago
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