Ask question

Ask question

All categories

2 years ago

14

Help me quick with my assignment please thank u

1 answer:

nordsb [41]2 years ago

4 0

Answer is C. Hope this helped

You might be interested in

What is the 6th term of the sequence?

vesna_86 [32]

Answer:

i really dont know maybe 6

Step-by-step explanation:

5 0

3 years ago

Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo

Zepler [3.9K]

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period 2 is 9

Forecast can be given by

$F_{t+1}=F_t+\alpha (D_t-F_t)$

where

$F_{t+1}=Future Forecast$

$F_t=Present\ Period\ Forecast$

$D_t=Present\ Period\ Demand$

$\alpha =smoothing\ constant$

$F_{t+1}=5+0.2(7-5)$

$F_{t+1}=5.4$

Forecast for Period 3

$F_{t+2}=F_{t+1}+\alpha (D_{t+1}-F_{t+1})$

$F_{t+2}=5.4+0.2\cdot (9-5.4)$

$F_{t+2}=6.12$

8 0

3 years ago

What is the x-coordinate of the solution to the following system of equations?

tatyana61 [14]

Answer

X-2y = 2

3x + y = 6

Ox=-2

Ox=0

Ox=2

Ox=3

= 0

Step-by-step explanation:

easy

8 0

2 years ago

If y has moment-generating function m(t) = e 6(e t −1) , what is p(|y − µ| ≤ 2σ)?

Lostsunrise [7]

Since $\mathrm M_Y(t)=e^{6(e^t-1}$ , we know that $Y$ follows a Poisson distribution with parameter $\lambda=6$ .

Now assuming $\mu,\sigma$ denote the mean and standard deviation of $Y$ , respectively, then we know right away that $\mu=6$ and $\sigma=\sqrt6$ .

So,

$\mathbb P(|Y-\mu|\le2\sigma)=\mathbb P(6-2\sqrt6\le Y\le6+2\sqrt6)=\dfrac{66366}{175e^6}\approx0.940028$

6 0

3 years ago

Find the area of the shape shown<br> below.

Allisa [31]

Answer:

The area of the figure is 28 units².

Step-by-step explanation:

Find the area of the full rectangle, ignoring the triangle.

$a = lw \\ a = 4 \times 8 = 32$

Then, find the area of the triangle:

$a = \frac{bh}{2} \\ a = \frac{2 \times 4}{2} \\ a = 4$

Finally, subtract:

$32 - 4 = 28$

7 0

3 years ago