Answer: 
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Explanation:
We start with y = 1/x
Vertically stretching it by a factor of 4 gets us to y = 4/x. Simply multiply the right hand side by 4.
Then reflecting over the y axis means we replace every x with -x to get y = 4/(-x) but that simplifies to y = -4/x. So we can see that any y axis reflection is identical to an x axis reflection, and vice versa. This is due to the symmetry of hyperbolas like this.
Next, we replace x with (x+5) so that we shift the xy axis 5 units to the right, giving the illusion the curve shifts 5 units to the left.
Lastly, we tack on a +4 to shift the graph up 4 units.
The final result is
Hello :
the tangent has same slope of the line 16x -y +5 = 0 because parallel.
y = 16x + 5
the slope is : 16
but : f'(x) = 16
f'(x) = 16x^3 - 16x +16
solve : 16x^3 - 16x +16 = 16
x^3 - x +1 =1
x^3 - x = 0
x(x² - 1 ) =0
x(x -1 )(x +1) =0
x=0 or x-1 =0 or x +1= 0
x=0 or x = 1 or x = -1
if : x = 0 : y = 4(0)^4 -8(0)^2+16(0) +7 =7
if : x =1 : y = 4(1)^4 -8(1)^2+16(1) +7 = 19
if : x = -1 : y = 4(-1)^4 -8(-1)^2+16(-1) +7 = -13
<span>the points : A(0,7) , B(1 , 19) , c ( -1 , -13)</span>
To find the circumference, you will use the formula for finding circumference of a circle.
I used the true value of pi for the calculations.
C = pi x d
pi x 27.13
C = 85.77mm
2x^2 - 3 = -4x - 1
2x^2 + 4x - 3 + 1 = 0
2^2 + 4x - 2 = 0 <==
