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Mademuasel [1]
3 years ago
8

1. *

Mathematics
1 answer:
julsineya [31]3 years ago
8 0

Answer:

Her multiplication

Step-by-step explanation:

Not really an aexplanation

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3^x+2=8^x-1 Solve for x.
zubka84 [21]

I assume the equation is supposed to be

3^{x+2}=8^{x-1}

Then we can write

9\cdot3^x=\dfrac18\cdot8^x\implies\left(\dfrac38\right)^x=\dfrac1{72}

Take the logarithm of base 3/8 on both sides:

\log_{3/8}\left(\dfrac38\right)^x=\log_{3/8}\dfrac1{72}

\implies x\log_{3/8}\dfrac38=-\log_{3/8}72

\implies x=-\log_{3/8}72

- - -

If the equation is actually 3^x+2=8^x-1, I'm afraid it cannot be solved exactly.

5 0
3 years ago
PLEASE ANSWER ASAP!!!! ILL MAKE YOU BRAINIEST!!!<br><br> What is the length of XY?
JulijaS [17]
Not sure, but i think it's 4
6 0
3 years ago
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Ht) = -16t+32t+ 10.​
KonstantinChe [14]
Answer:
16t + 10

Explanation:
Step 1 - Add like terms

-16t + 32t + 10
16t + 10
5 0
3 years ago
At school the maximum number of students that can be in a classroom is 25. If there are 17 students signed up for the geometry c
siniylev [52]
8 students can join because 25-17 is 8
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3 years ago
Which table represents a quadratic relationship?
svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0
3 years ago
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