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Sindrei [870]
2 years ago
13

The image below shows an encoding for a black and white pixel image. The first two

Computers and Technology
1 answer:
GREYUIT [131]2 years ago
5 0

Answer:

where is the image i need the image

Explanation:

You might be interested in
Write the function definition for a function called list_total that accepts a list of integers
uranmaximum [27]

Answer:

def list_total(numbers):

   sum_of_numbers = 0

   for number in numbers:

       sum_of_numbers += number

   return sum_of_numbers

Explanation:

So, to define a function, the syntax is simply:

def functionName(arguments here):

   # code

So to define a function called "list_total" which accepts a list of integers, you write:

"

def list_total(numbers):
   # code

"

any the "numbers" is a parameter, and it's just like any variable, so you can name it anything besides keywords. I just named it "numbers" since it makes sense in this context, you could also write "integers" instead and it would be just as valid, and may be a bit more specific in this case.

Anyways from here, the initial sum should be equal to 0, and from there we add each number in the list to that initial sum. This can be done by initializing a variable to the value "0" and then traversing the list using a for loop. This can be done as such:

"

def list_total(numbers):

   sum_of_numbers = 0

   for number in numbers:

       # code

"

So for each element or integer in the list "numbers" the for lop will run, and the variable "number" will contain the value of the current element it's on.

So we can add the "number" to the sum_of_numbers as such:

sum_of_numbers = sum_of_numbers + number

but there is a shorter way to do this, and it's represented as:

sum_of_numbers += sum_of_numbers

which will do the same exact thing. In fact this works for any mathematical operation for example:

a *= 3

is the same thing as

a = a * 3

and

a /= 3

is the same thing as

a = a / 3

It's the same thing, but it's a much shorter and more readable notation.

Anyways, this code will go in the for loop to almost finish the code

"

def list_total(numbers):

   sum_of_numbers = 0

   for number in numbers:

       sum_of_numbers += number

"

The last thing is to return this value, and this is simply done by using the syntax:

"return {value here}"

and since the sum_of_numbers has the value, we write

"return sum_of_numbers"

at the end of the function, which is very very important, because when you use the return keyword, you end the function, and return whatever value is next to the return to the function call

So to finish the code we just add this last piece to get:

"

def list_total(numbers):

   sum_of_numbers = 0

   for number in numbers:

       sum_of_numbers += number

   return sum_of_numbers

"

7 0
2 years ago
"write a program to play and score the paper-rock-scissor game. each of two users types in either p, r, or s. the program then a
algol13

The program is an illustration of conditional statements.

Conditional statements are used to execute instructions, if and only if certain <em>condition or conditions </em>are met.

Take for instance: <em>If b = 5, print "ab"</em>

The above print statement will only be executed, if the <em>value of b is 5</em>

The paper-rock-scissor program in Python where comments are used to explain each line is as follows,  

#This imports the random module

import random

#This is used to control the repetition of the game

playagain ="T"

#The following is repeated until the user chooses not to play again

while(playagain == "T"):

   #This generates a random choice for the computer

   computer = random.choice(['Rock', 'Paper', 'Scissors'])

   #This gets input for the player

   player = input('Choose: ')

   #If the player and computer choose the selection

   if player == computer:

       #Then, it's a tie

       print('A tie - Both players chose '+player)

   #If the player wins

   elif (player.lower() == "Rock".lower() and computer.lower() == "Scissors".lower()) or (player.lower() == "Paper".lower() and computer.lower() == "Rock".lower()) or (player == "Scissors" and computer.lower() == "Paper".lower()):

       #This prints "player won" and the reason

       print('Player won! '+player +' beats '+computer)

   #If otherwise,

   else:

       #This prints "computer won" and the reason

       print('Computer won! '+computer+' beats '+player)

   #This asks if the player wants to play again

   playagain = input("Play again? T/F: ")

At the end of each round,

  • The program displays the winner
  • Or prints a tie, if there's a tie

See attachment for sample run

Read more about conditional statements at:

brainly.com/question/22078945

8 0
2 years ago
I need help<br> plsssssssss
Misha Larkins [42]
The factorial of 4 is 24
4 0
3 years ago
What does the headgear of a mine do
deff fn [24]
Hard to answer to short but I will try the head gear let's you talk to people on the internet
5 0
3 years ago
Read 2 more answers
Given the String variables name1 and name2, write a fragment of code that assigns the larger of the two to the variable first (a
Neporo4naja [7]

Answer:

if ( name1 > name2) {

    first = name1;

} else {

    first = name2;

}

Explanation:

First you need take a decision for that reason you need and if - else structure to decide if asign the variable name1 or the variable name2 to the result. Later you can use an > or < to compare two strings because it use the ASCII code to compare wich one is larger than another.

if ( name1 > name2) {

    first = name1;

} else {

    first = name2;

}

6 0
3 years ago
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