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3241004551 [841]
3 years ago
15

How many ways can I choose a president, vice-president, secretary and treasurer for student council from a group of 13 students?

(Hint: Does order matter?)
Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0
There are 17160 ways to choose
You might be interested in
Express 3m24cm in kilometers,leaving your answer in standard form​
erastova [34]

Answer:

0.00324 kilometres

Step-by-step explanation:

Remember:

100 centimeters = 1 meter

1000 meters = 1 kilometer

So first, let's add together the meters and centimeters. To do that, we have to convert the meters to centimeters. That would become 300 centimeters, then you add the 24 centimeters to get 324 centimeters. Then, you convert that to kilometers. You can use a calculator for this, but I'll show you how to do this without a calculator. Since 100 centimeters is one meter, and 1000 meters equals to one kilometer, there would be 5 spaces from 324 to our answer, so you move the invisible decimal point 5 spaces to the left, and you get your answer, which is 0.00324 kilometres!

7 0
3 years ago
Read 2 more answers
IN ΔBCD line N is the perpendicular bisector of BC and line M is the perpendicular bisector of CD
Helga [31]

Answer:

Correct answer is D(the intersection of lines N and M)

Step-by-step explanation:

we Know that  circumcenter of a triangle is  point at which the perpendicular bisectors of the sides of a triangle intersect and which is equidistant from the three vertices. In other words circumcenter of a triangle is the center of the circle which  passes through the vertices of the triangle. It means, any side of the triangle will act as a chord of the circumcircle. Hence the circumcenter of a triangle must lie on the perpendicular bisectors of the sides. therefore the intersection of line N and M must be  circumcenter of the triangle.

I hope this answer will help you

4 0
3 years ago
How many solutions does the equation |x + 6| − 4 = c have if c = 5? If c = −10? Complete the explanation
mixer [17]

Answer:

<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>

Step-by-step explanation:

We know

|a|\geq0

for any real value of <em>a</em>.

|a| = b > 0 -  <em>two solutions: </em>a = b or a = -b

|a| = 0 - <em>one solution: a = 0</em>

|a| = b < 0 - <em>no solution</em>

<em />

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5           <em>add 4 to both sides</em>

|x + 6| = 9 > 0   <em>TWO SOLUTIONS</em>

for c = -10

|x + 6| - 4 = -10           <em>add 4 to both sides</em>

|x + 6| = -6 < 0   <em>NO SOLUTIONS</em>

<em></em>

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         <em>subtract 6 from both sides</em>

x = 3 or x = -15

5 0
3 years ago
Consider the following system:
Goryan [66]
You did not include the choices. However, I answered one that just included them. I've included the possible answers below and then the correct answers. 

<span>A multiple of Equation 1. 
B. The sum of Equation 1 and Equation 2 
C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2. 
D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2. 
E. The sum of a multiple of Equation 1 and Equation 2.

</span>A, B and E.

Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D. 
4 0
3 years ago
Read 2 more answers
2+2..................​
Nana76 [90]

Answer:

4..............21...........

4 0
3 years ago
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