Question

A car tire with a diameter of 1.6 ft rotates 275 degrees . How far does a point on the circumference of the tire travel

Answer 1

Answer:

A point on the circumference of the tire will travel 7.68 ft.

Step-by-step explanation:

Given;

radius of the car tire, r = 1.6 ft

angular distance or rotation = 275⁰

A complete rotation of the tire = 360⁰

the distance a point on the circumference will travel = 2πr

If 360⁰ = 2πr

then 275⁰ = ?

$= \frac{275 \ \times \ 2\pi r}{360} = \frac{275 \ \times \ 2\pi \times 1.6ft}{360} = 7.68 \ ft$

Therefore, a point on the circumference of the tire will travel 7.68 ft.