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Bess [88]
3 years ago
8

A car tire with a diameter of 1.6 ft rotates 275 degrees . How far does a point on the circumference of the tire travel

Mathematics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

A point on the circumference of the tire will travel 7.68 ft.

Step-by-step explanation:

Given;

radius of the car tire, r = 1.6 ft

angular distance or rotation = 275⁰

A complete rotation of the tire = 360⁰

the distance a point on the circumference will travel = 2πr

If 360⁰ = 2πr

then 275⁰ = ?

= \frac{275 \ \times \ 2\pi r}{360} = \frac{275 \ \times \ 2\pi \times 1.6ft}{360} = 7.68 \ ft

Therefore, a point on the circumference of the tire will travel 7.68 ft.

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The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0
3 years ago
Write 9x - 8 as a verbal expression <br><br> Please the fast as possible!
Natalka [10]

Answer:

8 subtracted from the product of 9 and x

Hope this helps!

4 0
2 years ago
Make <br> x<br> the subject of the formula<br> x<br> −<br> 3<br> =<br> q
lakkis [162]

Answer:

x = q + 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

x - 3 = q

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 3 to both sides:          x = q + 3
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2 years ago
The distance between two stations A and B is 100km.If the average speed of a train is increased by 5km/h , the time taken by the
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Answer:

I also occupy it they pass it to me

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2 years ago
Please help me I need hlp
MatroZZZ [7]
H = 27 m. Since these are scales of each other, you can solve for h by creating a ratio of the two lengths. Divide 36 by 4 to find the scale for the tree. 36/4 = 9. This means that the large triangle is 9 times larger than the small one. Now to find h, multiply the height of the small triangle by the scale. 3 x 9 = 27. This means the height, h, of the large triangle is 27 m. You can check this by dividing the length of each triangle by their height. If they are the same number, the scale is correct. 36/27 = 1.33, 4/3 = 1.33 ✅
5 0
3 years ago
Read 2 more answers
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