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Svetach [21]
2 years ago
11

For the function f(x) =x 1/5 /8, find f-1(x)

Mathematics
1 answer:
irakobra [83]2 years ago
4 0

Second option is correct

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4 mi = ___ ft <br> answer please!!
Tpy6a [65]

Answer:

21120

Step-by-step explanation:

1 mile = 5280 feet

5280 feet * 4 = 21120

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3 years ago
a sphere has a diameter of 7 centimeters what is the surface area is 3.14 to approximate Pi round to the nearest hundredth if ne
Over [174]
Good idea to look up the formula for "surface area of a sphere" and to write it down for later reference.  It is A=4 pi r^2, where r is the radius of the sphere.
If the given sphere has a diameter of 7 cm, what is the radius of this sphere?

Write your answer inside the parentheses, below:

Sphere surface area = 4 pi (r)^2, or (in this case), A = 4(3.14)(        )^2
8 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST THANK YOU
Tanya [424]

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6? I'm not sure honestly

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2 years ago
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2 years ago
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A company developing a new cellular phone plan intends to market their new phone to customers who use text and social media ofte
Ber [7]

Answer:

A customer who sends 78 messages per day would be at 99.38th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average of 48 texts per day with a standard deviation of 12.

This means that \mu = 48, \sigma = 12

a. A customer who sends 78 messages per day would correspond to what percentile?

The percentile is the p-value of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 48}{12}

Z = 2.5

Z = 2.5 has a p-value of 0.9938.

0.9938*100% = 99.38%.

A customer who sends 78 messages per day would be at 99.38th percentile.

8 0
2 years ago
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