I would use a small, easy slope.
To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
Step-by-step explanation:
B/-7 = 4
Cross multiple
-7×4 = B
-28 = B
There is a line and a parabola in the graph.
So, we will get the solution set from the point of intersection of both line and parabola.
Notice that the parabola and the line intersecting at two points E(1, 5) and C(-0.5,2).
So, the solution set is E(1, 5) and C(-0.5,2).
X=8-y
2(8-y)=10
16-2y=10
-2y=10-16
-2y=-6
y=3
x+3=8
x=8-3
x=5
(5,3) is the answer :)
