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Rzqust [24]
3 years ago
13

Each big square below represents one whole. What percent is represented by the shaded area?

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

173%

Step-by-step explanation:

I think?

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Which piecewise relation defines a function?
RideAnS [48]
Answer: h(x)

Explanation:

1) f(x) is not a function because there is an ambiguity for x = 4.

x = 4 belongs to both intervals - 2 ≤ x ≤ 4 and x ≥ 4

Then you find two different possible images for x: 0 and -(2)^2 = - 4.

That makes that f(x) be not a function.

2) similar thing happens with g(x)

as per the given relation the value of g(x) for x = 2 is 4 and 4+1 = 5. Which makes that g(x) be not a function.

3) j(x) is not a function because the image of x = -4 is -3(-4) = 12 and 3.

4) h(x) is a function, because there is not any ambiguity in its definition, for every x in its domain there is only one image h(x).
8 0
3 years ago
Read 2 more answers
16.11 ÷ 99<br> 19.6 ÷ 20 <br> 0.9 ÷ 11<br> 50.8 ÷ 45<br> 0.1414 ÷ 2 <br> 0.213 ÷ 31
ANEK [815]
BEFORE YOU USE THE ANSWERS! I USED CALCULATOR AND IT TOLD ME THIS SO IM NOT SO SURE IF IM CORRECT!!
1: 0.16272727272
2: 0.98
3: 0.08181818181
4: 1.12888888889
5: 0.0707
6: 0.00687096774
4 0
3 years ago
Need help please help
aleksandrvk [35]

okokok

Step-by-step explanation:

5 0
3 years ago
In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.
Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

j = \sqrt{99.45}

j = 9.97

∴

\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}

{9.97 \times    Sin (L ) = (2.7 \times Sin \ 43)

=  Sin \ L = \dfrac{ (2.7 \times Sin \ 43)}{9.97 } \\ \\ =  Sin \ L = \dfrac{ (2.7 \times 0.6819)}{9.97 }  \\ \\  = Sin \ L = 0.18466 \\ \\  L = Sin^{-1} (0.18466) \\ \\  L = 10.64 ^0

3 0
3 years ago
What elements are found in the universal set but not in sets an or b?​
GaryK [48]

Answer:

Complement of a Set If U is a universal set and A is a subset of U, then the set of all elements in U that are not in A is called the complement of A and is denoted Ac.

Step-by-step explanation:

8 0
2 years ago
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