Answer:
Step-by-step explanation:
The integral from a to 4 is ...

We want the value of this to be 12, so we can write ...
-3/2a^2 +a +20 = 12
3a^2 -2a -16 = 0 . . . . . subtract the left side and multiply by 2
(3a -8)(a +2) = 0 . . . . . factor
a = 8/3 or -2 . . . . . . . .values of a that make the factors zero
The only possible values of a are 8/3 and -2.
Answer:
m = 4/3
Step-by-step explanation:
Two ways to do this problem.
Method 1 change the Method 2 If a linear equation is in
equation to slope-intercept form standard form, ax =by = c then
8x - 6y = 1 the slope = -a/b
-6y = -8x + 1 In 8x - 6y = 1 a = 8 and b = -6
y = (-8x)/-6 +1/-6 So m = - (8)/-6 = 8/6 = 4/3
m = -8/-6= 4/3
Note: Method 2 only works if the equation is in standard form.
Answer:
1542
Step-by-step explanation:

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Answer:
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Step-by-step explanation: