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Darya [45]
3 years ago
7

PLEASE HELP ASAP PLZZ I WILL GIVE BRAINLIEST In order to increase the circumference of a circle from 12pi cm to 18pi cm, by how

much must the diameter increase?​
Mathematics
2 answers:
klasskru [66]3 years ago
5 0

Answer:

<u>Diameter of first circle</u> = 2πr/π = d

  • 12π/π
  • 12cm.

<u>Diameter of second circle</u> = 2πr/π = d

  • 18π/π
  • 18cm.

<u>Diameter increases</u> = 18cm - 12cm

  • 6cm.

pshichka [43]3 years ago
3 0

Answer:

This is because the diameter of the smaller circle is 12pi/pi which is 12, and the diameter of the bigger one is 18pi/pi which is 18. 12 + 6 = 18, so the diameter increases by 6.

Step-by-step explanation:

brinliest pls

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Type the correct answer in each box. Use numerals instead of words.
N76 [4]

The simplification of the polynomial expression will give 3x² - 20x + 8.

<h3>How to illustrate the polynomial?</h3>

The polynomial expression is given as:

(5x² + 13x4) (17x² + 7x - 19) + (5x-7)(3x + 1)

= 5x² + 13x - 4 - 17x² - 7x + 19 + 15x² + 5x - 21x - 7

Then collect like terms

= 5x² + 15x² - 17x² + (13x - 7x + 5x - 21x) - 4 - 7 + 19

= 3x² - 20x + 8.

Learn more about polynomial on:

brainly.com/question/2833285

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The number obtained on rationalizing the denominator of 1/(√7--2) is
Slav-nsk [51]

\frac{1}{ \sqrt{7}  -(- 2)}  \\ rationalizing \:  \:  \: the \:  \:  \: denominator \:  \:  \: we \:  \:  \: have \\  =  \frac{1}{ \sqrt{7} + 2 }  \times  \frac{ \sqrt{7}  - 2}{ \sqrt{7}  - 2}  \\  =  \frac{ \sqrt{7}  - 2}{ {( \sqrt{7} )}^{2} -  {(2)}^{2}  }  \\  =  \frac{ \sqrt{7} - 2 }{7 - 4}  \\  =  \frac{ \sqrt{7}   - 2}{3}

Hope you could get an idea from here.

Doubt clarification - use comment section.

3 0
3 years ago
Read 2 more answers
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