What is the answer 6a+5a-b-5b+2a
2 answers:
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Answer:
The pvalue of the test is 0.3844 > 0.1, which means that there is not sufficient evidence at the 0.10 level to support the executive's claim
Step-by-step explanation:
A publisher reports that 35% of their readers own a laptop.
This means that the null hypothesis is:
A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.
This means that the alternate hypothesis is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.35 is tested at the null hypothesis:
This means that
A random sample of 190 found that 32% of the readers owned a laptop.
This means that
Z-statistic:
pvalue of the test and decision:
As we are testing that the mean is different from a value and z is negative, the pvalue of the test is 2 multiplied by the pvalue of z = -0.87
Looking at the z-table, z = -0.87 has a pvalue of 0.1922
2*0.1922 = 0.3844
0.3844 > 0.1, which means that there is not sufficient evidence at the 0.10 level to support the executive's claim
I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is
and the number of ways of drawing 3 aces and 2 2s is the same,
so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is
The total number of hands that can be drawn is
Then the probability of getting a full house is