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mina [271]
3 years ago
13

Here are two datasets:

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0

Answer:

Option a) Mean

Mean is affected a lot by the change in the last observation as the median remains the same.

Step-by-step explanation:

we are given the following in the question:

Data set A: 64, 65, 66, 68, 70, 71, 72

Data set B: 64, 65, 66, 68, 70, 71, 720

For data set A, the mean and median are 68.

For data set B:

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1124}{7} = 160.57

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data:

64, 65, 66, 68, 70, 71, 720

\text{Median} = \dfrac{7+1}{2}^{th} \text{ term} = 4^th\text{ term} = 68

Clearly, 720 is the is a outlier.

As seen mean is affected a lot by the change in the last observation as the median remains the same.

You might be interested in
N × $3.05 = $305.00=
sdas [7]

Answer:

n = 100

Step-by-step explanation:

Step 1:

n × $3.05 = $305            Equation

Step 2:

n = $305 ÷ $3.05          Divide

Answer:

n = 100

Hope This Helps :)

4 0
3 years ago
A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the
Vedmedyk [2.9K]
(a) Using Newton's Law of Cooling, \dfrac{dT}{dt} = k(T - T_s), we have \dfrac{dT}{dt} = k(T - 75) where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get \dfrac{dT}{T - 75} = k dt. Integrate both sides to get \ln|T - 75| = kt + C.

Since T(0) = 185, we solve for C:
|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110
So we get \ln|T - 75| = kt + \ln 110. Use T(30) = 150 to solve for k:
\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)

So

\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t}  \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}

But choose Positive because T > 75. Temp of turkey can't go under.

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)}  = 136.929 \approx 137{}^{\circ}F

(b)

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30}  \\
100 = 75 + 110(15/22)^{t/30}   \\
25 = 110(15/22)^{t/30}  
\frac{25}{110} = (15/22)^{t/30}   \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22)  \approx 116\ \mathrm{min}

Dogs of the AMS.
4 0
3 years ago
Please answer this correctly which is the correct options
MakcuM [25]

The first two are equivalent to 15 = k + 13

8 = k + 13 - 7 → ( add 7 to both sides )

8 + 7 = k + 13 ⇒ 15 = k + 13 ' is equivalent '

12 = k + 13 - 3 → ( add 3 to both sides )

12 + 3 = k + 13 ' is equivalent '


4 0
3 years ago
If the range of the function f(x)=x/4 is {28, 30, 32, 34, 36}, what is its domain?
avanturin [10]
Y = x/4
x = 4y
domain = {4(28), 4(30), 4(32), 4(34), 4(36)} = {112, 120, 128, 136, 144}
4 0
3 years ago
What is 65% of 97?do NOT round your answer
Softa [21]
The answer is 63.05
Tip-search it up
7 0
3 years ago
Read 2 more answers
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