Answer:
0.180144 < p < 0.339856
Step-by-step explanation:
According to the Question,
- Given That, Out of 200 people sampled, 52 had kids, Thus the proportion of the mean is 52/200 = 0.26
⇒
standard error of the sample is square root(0.26 * (1-0.26) / 200) = 0.031
⇒alpha(a) = 1 - 99/100 = 0.01
⇒critical probability(p*) = 1 - a/2 = 0.995
⇒assuming a normal distribution, look for the z-score associated with 0.995 cumulative probability
, z-score = 2.576
⇒margin of error(ME) = 2.576 * 0.031 = 0.079856
-
the confidence interval is 0.26 + or - 0.079856
0.180144 < p < 0.339856
