Question

Quadrilateral MNQP has vertices as shown. If the figure is translated 4 units left and 3 units down, what are the coordinates of N'? *

Answer 1

Answer:    (-3, 0)

Explanation:

Point N is at (1,3)

We apply the rule $(x,y) \to (x-4,y-3)$ which will translate the point 4 units to the left and 3 units down.

The old x coordinate x = 1 becomes x-4 = 1-4 = -3

The old y coordinate y = 3 becomes y-3 = 3-3 = 0

The point N(1,3) moves to N ' (-3, 0)