Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
The answer of 799/4 is equal 1
Answer:
7$
Step-by-step explanation:
15+6=21 ÷3 = $7 per friend
Hello!
To find the interquartile range, subtract the value of the upper quartile from the value of the lower quartile.
33 - 25 = 8
The interquartile range is 8. Hope I helped! :3
Answer:
I think it's A. 7
Step-by-step explanation:
