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Alexeev081 [22]
4 years ago
6

Jennifer is making bouquets of flowers. She has 25 roses, 45 tulips, and 15 snapdragons. She divides the flowers equally to make

as many bouquets as possible. She uses up all the flowers. What number of snapdragons are in each bouquet?
a. 3
b.5
c.9
d.15
Mathematics
2 answers:
chubhunter [2.5K]4 years ago
8 0

Answer:

a. 3

Step-by-step explanation:

The number of flowers should be divisible by the number of bouquets.

Since

25 = 5 \times 5 \\ 45 = 5 \times 9 \\ 15 = 5 \times 3

there should be 5 bouquets, and each bouquet has 5 roses, 9 tulips and 3 snapdragons.

so the answer is

a. 3

Alexus [3.1K]4 years ago
4 0

Answer:

A. 3

Step-by-step explanation:

45 + 15 + 25 = 85

There are 85 flowers.

There are 25 roses, 45 tulips, an 15 roses.

What are all 3 of these divisible by?

5!

That means that there will be 5 bouquets.

Let's divide each number by 5 to find out how many of each type of flower is in each bouquet.

25/5 = 5

5 roses in each bouquet

45/5 = 9

9 tulips in each bouquet

15/5 = 3

3 snapdragons in each bouquet

5 + 9 + 3 = 17

There are a total of 17 flowers in each bouquet.

Out of those 17 flowers, 3 are snapdragons.

A. 3

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Answer:

\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{1394}{88}=15.8

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Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

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Solution to the problem

For this case we can calculate the properties required with the following table:

Interval     Mid point (x)     f           x*f         x^2 *f

_________________________________________

1-10               5.5               40        220         1210

11-20             15.5              15        232.5       3603.75

21-30            25.5             23       586.5       14955.75

>31                35.5             10        355          12602.5

________________________________________

Total                                 88        1394         32372

We assume that the mid point for the class >31 is 35.5 using the problem information.

For this case the expected value would be given by:

\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{1394}{88}=15.8

The variance owuld be given by this formula"

s^2 = \frac{n(\sum x^2 f) -(\sum xf)^2}{n(n-1}

And if we replace we got:

s^2 = \frac{88(32372) -(1394)^2}{88(88-1}=118.3

The standard deviation would be just the square root of the variance:

Sd(X) = \sqrt{118.273}=10.9

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