Question

4. Given directed line segment CD, if point E divides CD three-fourths of the way from C to D, find the coordinates of E, then plot E.​

Answer 1

Answer:

Point E is given by $\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )$

Step-by-step explanation:

Let points C and D be $(x_0,y_0),\,(x_1,y_1)$ and let point E divides it in ratio $m:n$.

Then coordinates of point E are given by $\left ( \frac{mx_1+nx_0}{m+n},\frac{my_1+ny_0}{m+n} \right )$

Put $m:n=3:4$

Point E is given by $\left ( \frac{3mx_1+4x_0}{3+4},\frac{3y_1+4y_0}{3+4} \right )=\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )$

Now plot point E.

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