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Valentin [98]
2 years ago
10

THIS IS ME WHEM I AM SMALL CUTE RIGHT?​

Mathematics
2 answers:
RUDIKE [14]2 years ago
8 0

Answer:

lol u look like fez from that 70s show

Nezavi [6.7K]2 years ago
5 0
Nahhh bro what are you doing
You might be interested in
Which polynomial equations have -i as one of their roots?
pochemuha
I = sqrt(-1)
i^2 = -1
(-i)^2 = (-i)(-i) = i^2 = -1
(-i)^3 = (-i)(-i)(-i) = (-i)(i^2) = i

use these facts to find which equation is correct if x = -i

i bet on 2,3 or 4
8 0
2 years ago
Find the measure of each interior angles of a regular hexagon show all work
Ivahew [28]
The measure of the interior angles would be 120°, and they would all add up to be 720°
8 0
2 years ago
Can someone please check my answer
lyudmila [28]

Answer:

less

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
50 multiplied by 100
ra1l [238]
When multiplying by 100 just add 2 zero's behind your second number. ANSWER:5,000
3 0
3 years ago
Describe a scenario where the function value exists at x=c, but the limit does not exist.
Vikki [24]

The scenario can be described using a piecewise function like:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

<h3>When the value exists but the limit does not?</h3>

Remember that the limit only exists if the limit from left and the limit from the right give the same value.

Then, we can just define a piecewise function of the form:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Clearly, this is not a continuous function.

Notice that:

f(c) = c.\\\\ \lim_{x \to c^{-}} f(x) = 1/c\\\\ \lim_{x \to c^{+}} f(x) = 1/(c + 73)

So the limits from left and right are different, then:

\lim_{x \to c^{}} f(x)

Does not exist.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
2 years ago
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