Answer:
a.The phenotypic proportions obtained after having the genotypes are 50% marbled seeds, 25% spotted and dotted seeds since they are codominant, 25% spotted seeds.
b. Taking into account the F1 genotypes in the previous point, the expected phenotypes for the first crossing are 100% marbled seeds and for the second crossing 100% dotted seeds.
Explanation:
Let's suppose:
Marbled allele: M
Spotted allele: S
Dotted allele: D
Allele for Clear: C
a. Because both crosses were between homozygous parents, the entire F1 genotype is the same.
For the first crossing the descendants have the MS genotype, and for the second crossing the descendants have the DC genotype. It is enough to make a Punnett square to obtain the different combinations of genotypes between the crossing of MS and DC.
The correct answer is Certain flightless beetles have wings. Their wings are an example of an adapted structure.
These beetles have adapted structure in them and it is inherited from their ancestor's gene pool. as the time passes by the flightless beetles don't have wings as it was not needed but later become adopted due to environmental needs.
<h3>What is adapted structure?</h3>
Thick, hardened beetle wings, called elytra, cover the whole body and it has covered whole body of beetles. The adaptive features are inherited from their ancestor's gene pool.
Hence concluded that adapted structures in flightless beetles have wings. Their wings are an example.
To learn more about adapted structure refer to the link :
brainly.com/question/1213023
A. It has organelles enclosed in membranes
Each half would be a Hemisphere. I hope this helps.
