Answer:
96
Step-by-step explanation:
3*4*8=96
7x³ = 28x is our equation. We want its solutions.
When you have x and different powers, set the whole thing equal to zero.
7x³ = 28x
7x³ - 28x = 0
Now notice there's a common x in both terms. Let's factor it out.
x (7x² - 28) = 0
As 7 is a factor of 7 and 28, it too can be factored out.
x (7) (x² - 4) = 0
We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.
x (7) (x - 2) (x + 2) = 0
Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.
x = 0 -----> so x = 0
7 = 0 -----> no solution
x - 2 = 0 ----> so x = 2 after adding 2 to both sides
x + 2 = 0 ---> so = x - 2 after subtracting 2 to both sides
Thus the solutions are x = 0, x = 2, x = -2.
Why not draw the graph of y=|x|? It has a v-shape, and the vertex is at (0,0).
The graph of f(x) = |x| - 3 looks exactly the same, EXCEPT that the whole graph of |x| is shifted 3 units downward. The smallest value that y can have is therefore -3.
Can you now figure out the range of f(x)?
Answer:
The equation of the straight line is 4x +y = 1
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given points are (-1,5) and ( 2,-7)
Slope of the line
slope of the line m = -4
<u><em>Step(ii):-</em></u>
The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4
y - 5 = -4 ( x-(-1))
y -5 = -4 x -4
4 x + y -5 +4=0
4x +y -1 =0
<u><em>Final answer:-</em></u>
The equation of the straight line is 4x +y = 1
<u><em> </em></u>
Answer:
Point-slope form: y + 3= -1(x + 4)
Slope-intercept form: y = -1x - 7
y = m * x + b,
where:
m is the slope; and
b is the intercept of the y-axis.
