We have the following limit:
(8n2 + 5n + 2) / (3 + 2n)
Evaluating for n = inf we have:
(8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
(inf) / (inf)
We observe that we have an indetermination, which we must resolve.
Applying L'hopital we have:
(8n2 + 5n + 2) '/ (3 + 2n)'
(16n + 5) / (2)
Evaluating again for n = inf:
(16 (inf) + 5) / (2) = inf
Therefore, the limit tends to infinity.
Answer:
d.limit does not exist
Answer:
a:b = 2
Step-by-step explanation:
Here we need to operate with terms in order to arrive to a ratio a:b (or a/b).
We have:
2a−b/6 = b/3
Lets sum b/6 in both sides:
2a−b/6 + b/6 = b/3 + b/6
2a = b/3 + b/6
Now, we can multiply and divide b/3 by 2 to make a 6 appear on the denominator and sum it with b/6, this is, use common denominator:
2a = b/3*(2/2) + b/6
2a = 2b/6 + b/6
2a = 3b/6
2a = b/2, as 3/6 = 1/2
Now lets divide both sides by b to make an a/b appear:
2a/b = (b/2)/b
2a/b = 1/2
Finally, multiply both sides by (1/2) or divide by 2:
(2a/b)/2 = 2
a/b = 2
This is, a is twice as b. If b is 1 so a is 2; if b is 45 so a is 90, and so on.
Answer:
ok
Step-by-step explanation:
