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aleksandr82 [10.1K]
3 years ago
9

Simplify -7x+6y-6x , please help with this question thank you

Mathematics
2 answers:
Vladimir79 [104]3 years ago
6 0

- 13x + 6y
Kryger [21]3 years ago
3 0

-7x+6y-6x is simplified to be -13x+6y.

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(4/x - z/y=0) <br> (10/x+z/y=0)
galina1969 [7]

Answer:

Some of the other answers are good examples of solving a system of three equations in three unknowns, which is what this problem is asking. Though the simplest way to solve this problem is actually to notice that, if we sum the three equations, we get:

 

   X + Y = 10

   X + Z = 20

+  Y + Z = 24

----------------

2X + 2Y + 2Z = 54

 

Factoring out the 2, we have 2(X + Y + Z) = 54, and dividing both sides by 2 reveals that X + Y + Z = 27.

Step-by-step explanation:

hopefully this helps

4 0
3 years ago
Can you help me, please
ehidna [41]

Answer:a.100+(hx25)

b.120+(hx20)

c.4 hours

h=hours

Step-by-step explanation:

4 0
3 years ago
Determine the principal value of the function: Arc sin(square root of 3/2)
Drupady [299]

Answer:

π/3

Step-by-step explanation:

We have to find the principal value of \text{arc sin}(\frac{\sqrt{3}}{2} )

arc sin means sin inverse. The sin inverse is a one to one function with its range between -\frac{\pi}{2} \textrm{ to } \frac{\pi}{2}

The principal value of the arc sin will lie within the above given range.

value of sin (60) or sin(\frac{\pi}{3}) is \frac{\sqrt{3}}{2}.

\frac{\pi}{3} lies between -\frac{\pi}{2}\textrm{ and } \frac{\pi}{2}

So, from here we can say that the Principal Value of Arc sin(square root of 3/2) is π/3

5 0
4 years ago
Is 1.5 greater than 3
Andre45 [30]
3 is greater than 1.5
5 0
3 years ago
Read 2 more answers
A manufacturer has been selling 1000 flat-screen TVs a week at $500 each. A market survey indicates that for A manufacturer has
luda_lava [24]

Answer:

a) Demand function: q=6000-10\cdot p

b) The rebate should be of $200, so the sale price becomes $300 per unit.

c) The rebate should be of $150, so the sale price becomes $350 per unit.

Step-by-step explanation:

a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).

We can express the demand function (linear) as:

q=b+m\cdot p

To calculate the slope m, we use:

m=\Delta q/\Delta p=(+100)/(-10)=-10

To calculate b, we use the known point and the calculated slope:

q=b+m\cdot p\\\\b=q-m\cdot p=1000-(-10)\cdot (500)=1000+5000=6000

Then the demand function is:

q=6000-10\cdot p

b) The revenue can be expressed as:

R=q\cdot p = (6000-10p)\cdot p=6000p-10p^2

To maximize, we can derive and equal to zero

dR/dp=6000-2*10p=0\\\\20p=6000\\\\p=300

The rebate should be of $200, so the sale price becomes $300 per unit.

c) If we take into account the cost, we have that

R=q\cdot p-C=(6000p-10p^2)-(68000+100q)\\\\R=(6000p-10p^2)-(68000+100(6000-10p))\\\\R=6000p-10p^2-(68000+600000-1000p)\\\\R=-10p^2+7000p-668000

To maximize, we can derive and equal to zero

dR/dp=-20p+7000=0\\\\p=7000/20=350

The rebate should be of $150, so the sale price becomes $350 per unit.

5 0
3 years ago
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