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Alexandra [31]
3 years ago
9

Select the correct answer. A car is moving at a constant speed along a straight line. Which statement is true about the forces a

cting on the car? A. The net force acting on the car from all directions is zero. B. The net force acting on the car is greater than the car's weight. C. The net force acting on the car is in the direction of the car's motion. D. The net force acting on the car is in the opposite direction of the car's motion.
Physics
2 answers:
agasfer [191]3 years ago
7 0

Answer:

i think try theanswer

Explanation:

proper

Tatiana [17]3 years ago
6 0

Answer:

A

Explanation:

For an object to move with constant speed the forward force is opposed by the effects of forces. There is no resultant force acting or constant speed is a result of no resultant force.

Newton's second law states that an object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity. Newton's Second Law states: F = ma. F is the net force acting on an object.

Also if velocity or speed is constant the acceleration will be 0 the F=m×0

F=0.

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leonid [27]

Answer:

Stratosphere and Thermosphere

Explanation: Both of these layers above earth heat as you go higher.

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3 years ago
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Part 1 - Basic Equations
bearhunter [10]

Answer:

1. λ = 2 L, 2.  v = 2L f₁ , 3.    v = √ T /μ², 4.   μ = 2,287 10⁻³ kg / m , 5.   Δv / v = 0.058 , 6.    Δμ /  μ = 0.12 , 7. Δ μ = 0.3  10⁻³ kg / m ,

8.  μ = (2.3 ±0.3)  10⁻³ kg / m

Explanation:

The speed of a wave is

            v = λ f                1

Where f is the frequency and λ the wavelength

     

The speed is given by the physical quantities of the system with the expression

            v = √ T /μ²                   2

1) The fundamental frequency of a string is when at the ends we have nodes and a maximum in the center, therefore this is

                 L = λ / 2

                 λ = 2 L

2) For this we substitute in equation 1

              v = 2L f₁

3) let's clear from equation 2

             

The speed of a wave is

            v = λ f₁

Where f is the frequency and Lam the wavelength

The speed is given by the physical quantities of the system with the expression

           v = √ T /μ²                            2

4) linear density is

           μ = T / (2 L f₁)²

           μ = 5.08 / (2 0.812 29.02)²

           μ = 2,287 10⁻³ kg / m

We maintain three significant length figures, so the result is reduced to

           μ = 2.29 10⁻³ kg / m

5) the speed of the wave is

            v = 2 L f₁

The fractional uncertainty is

         Δv / v = ΔL / L + Δf₁ / F₁

         Δv / v = 0.02 / 0.812 + 1 / 29.02

         Δv / v = 0.024 + 0.034

         Δv / v = 0.058

6) the equation for linear density is

              μ = T / (2 L f₁)²

             Δμ / μ = 2 ΔL / L + 2Δf₁ / f₁

The tension is an exact value therefore its uncertainty is zero ΔT = 0

            Δμ / μ = 2 0.02 / 0.812 + 2 1 / 29.02

             Δμ /  μ = 0.12

7) absolute uncertainty

           Δ μ = e_{r}   μ

           Δ μ = 0.12 2.29 10⁻³ kg / m

           Δ μ = 0.3  10⁻³ kg / m

8)

           μ = (2.3 ±0.3)  10⁻³ kg / m

8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
den301095 [7]
A: 0.7 -0.8 and 0hrs
B: 0.2 - 0.4 and 1.0 -1.1 hrs
C: 0-0.2 hrs and 0.8 - 1.0 hrs
D: 0.4 - 0.7 hrs
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3 years ago
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find the resistance of a multiplier connected with milliammeter of resistance 10 ohms with a deflection of 10 milliamperes and t
Murljashka [212]
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8 0
2 years ago
The electric output of a power plant is 716 MW. Cooling water is the main way heat from the powerplant is rejected, and it flows
Stels [109]

Answer:

(a) 83475 MW

(b) 85.8 %

Explanation:

Output power = 716 MW = 716 x 10^6 W

Amount of water flows, V = 1.35 x 10^8 L = 1.35 x 10^8 x 10^-3 m^3

mass of water, m = Volume  x density = 1.35 x 10^8 x 10^-3 x 1000

                                                               = 1.35 x 10^8 kg

Time, t = 1 hr = 3600 second

T1 = 25.4° C, T2 = 30.7° C

Specific heat of water, c = 4200 J/kg°C

(a) Total energy, Q = m x c x ΔT

Q = 1.35 x 10^8 x 4200 x (30.7 - 25.4) = 3 x 10^12 J

Power = Energy / time

Power input = P = \frac{3 \times 10^{12}}{3600}=8.35 \times 10^{8}W

Power input = 83475 MW

(b) The efficiency of the plant is defined as the ratio of output power to the input power.

\eta =\frac{Power output}{Power input}

\eta =\frac{716}{83475}=0.858

Thus, the efficiency is 85.8 %.

7 0
3 years ago
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