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Slav-nsk [51]
3 years ago
13

How is work involved in stopping a car?

Physics
2 answers:
horrorfan [7]3 years ago
8 0

................................

vichka [17]3 years ago
5 0
You have to move your foot to stop the car so I guess that would be considered work by moving your foot
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What power (in kW) is supplied to the starter motor of a large truck that draws 260 A of current from a 25.5 V battery hookup
joja [24]

Answer:

P = 6.63 kW

Explanation:

Given that,

Current, I = 260 A

Voltage of the battery, V = 25.5 V

We need to find the power supplied to the starter motor. We know that,

P = VI

Put all the values,

P = 25.5 × 260

P = 6630 W

or

P = 6.63 kW

So, the power supplied to the motor is 6.63 kW.

7 0
3 years ago
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A speeding motorist traveling 120 km/h passes a stationary police officer. The officer immediately begins pursuit at a constant
Lelu [443]
120 km/h = 33.33 m/s   10.8 km/h/s = 3 m/s/s     the motorist will cover a distance of 33.33 m x T(seconds)   the police officer will cover a distance of 1/2 (3) T^2   they will be at the same point when   33.33T = 1.5 T^2   33.33 = 1.5 T   3T = 66.66   T = 22.22 seconds   it will take the officer 22.22 seconds to catch the motorist.     the officer will be moving V=AT = 3m/s x 22.22 seconds = 66.66 m/s   almost 240 km/h (239.976 km/h)
8 0
4 years ago
Read 2 more answers
The only force acting on a 1.9 kg canister that is moving in an xy plane has a magnitude of 3.9 N. The canister initially has a
Hunter-Best [27]

Answer:

The work done on the canister is 15.34 J.

Explanation:

Given;

mass of canister, m = 1.9 kg

magnitude of force acting on x-y plane, F = 3.9 N

initial velocity of canister in positive x direction, v_i = 3.9 m/s

final velocity of the canister in positive y direction, v_j = 5.6 \ m/s

The change in the kinetic energy of the canister is equal to net work done on the canister by 3.9 N.

ΔK.E = W_{net}

ΔK.E = K.E_f -K.E_i

The initial kinetic energy of the canister;

K.E_i = \frac{1}{2} mv_i^2\\\\K.E_i = \frac{1}{2} m(\sqrt{v_i^2 +v_j^2 + v_z^2}\  )^2\\\\K.E_i = \frac{1}{2} *1.9(\sqrt{3.9^2 +0^2 + 0^2}\  )^2 = 14.45 \ J

The final kinetic energy of the canister;

K.E_f =\frac{1}{2} mv_j^2 \\\\K.E_f = \frac{1}{2} m(\sqrt{v_i^2 +v_j^2 + v_z^2}\  )^2\\\\K.E_f = \frac{1}{2} *1.9(\sqrt{0^2 +5.6^2 + 0^2}\  )^2 = 29.79 \ J

ΔK.E = 29.79 J - 14.45 J

ΔK.E = W_{net} = 15.34 J

Therefore, the work done on the canister is 15.34 J.

5 0
3 years ago
A Chinook salmon can jump out of water with a speed of 6.70 m/s6.70 m/s . How far horizontally dd can a Chinook salmon travel th
aksik [14]

Answer:

R = 3.88 m

Explanation:

As the Chinook salmon leaves the water till it gets back into the water it is performing a projectile motion with the following parameters:

V₀ = Launch Speed = 6.7 m/s

θ = Launch Angle = 29°

R= Range of Projectile= Horizontal Distance Covered by Chinook salmon= ?

The value of the range of a projectile is given by the following formula:

R = (V₀² Sin 2θ)/g

R = [(6.7 m/s)² Sin {(2)(29°)}/(9.8 m/s²)]

R = [(6.7 m/s)² Sin (58°)/(9.8 m/s²)]

<u>R = 3.88 m</u>

8 0
4 years ago
What wave moves in the same direction as the force that created it?
SIZIF [17.4K]
Longitudinal waves have movement in the direction of the wave energy.
3 0
3 years ago
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