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Slav-nsk [51]
3 years ago
13

How is work involved in stopping a car?

Physics
2 answers:
horrorfan [7]3 years ago
8 0

................................

vichka [17]3 years ago
5 0
You have to move your foot to stop the car so I guess that would be considered work by moving your foot
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One nanometer is equal to how many centimeters?
Neko [114]
One nanometer = 1e-7
4 0
3 years ago
Read 2 more answers
A rotating light is located 13 feet from a wall. The light completes one rotation every 3 seconds. Find the rate at which the li
saveliy_v [14]

Answer:

29.2 ft/s

Explanation:

The distance of the light's projection on the wall

y = 13 tan θ

where θ is the light's angle from perpendicular to the wall.

The light completes one rotation every 3 seconds, that is, 2π in 3 seconds,

Angular speed = w = (2π/3)

w = (θ/t)

θ = wt = (2πt/3)

(dθ/dt) = (2π/3)

y = 13 tan θ

(dy/dt) = 13 sec² θ (dθ/dt)

(dy/dt) = 13 sec² θ (2π/3)

(dy/dt) = (26π/3) sec² θ

when θ = 15°

(dy/dt) = (26π/3) sec² (15°)

(dy/dt) = 29.2 ft/s

5 0
3 years ago
Hello people ~
Pepsi [2]

Answer:

Potential

Explanation:

The most accurate term is Electrostatic potential energy

  • It is denoted as UC

It's named like this because the force between charges or electrons is called electrostatic force .

5 0
3 years ago
A student walks 100 m East and 100 m North. What is their distance traveled?
vichka [17]

--  The student's distance traveled is 200 meters.

--  The student's displacement is 141 meters Northeast.

5 0
3 years ago
A thin film of soap with n = 1.34 hanging in the air reflects dominantly red light with λ = 642 nm. What is the minimum thicknes
wariber [46]

Answer:

The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

Explanation:

Given that,

Refractive index of soap= 1.34

Refractive index  of glass= 1.55

Wavelength = 642 nm

(I). We need to calculate the minimum thickness

Using formula of thickness

t=\dfrac{(2m+1)\lambda}{4n}

Where, m = 0 for constrictive

Put the value into the formula

t=\dfrac{(642\times10^{-9})}{4\times1.34}

t=1.197\times10^{-7}\ m

(II). We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{2nt}{m}

Where, m = 1

Put the value into the formula

\lambda=\dfrac{2\times1.55\times1.197\times10^{-7}}{1}

\lambda=371\ nm

Hence, The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

6 0
3 years ago
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