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Slav-nsk [51]
3 years ago
13

How is work involved in stopping a car?

Physics
2 answers:
horrorfan [7]3 years ago
8 0

................................

vichka [17]3 years ago
5 0
You have to move your foot to stop the car so I guess that would be considered work by moving your foot
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Hey, earn points here
navik [9.2K]

Answer:yayyyy

Explanation:

4 0
3 years ago
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We divide the electromagnetic spectrum into six major categories of light, listed below. Rank these forms of light from left to
makkiz [27]

electromagnetic spectrum is consisting of many frequency range which is from gamma rays to radio waves

they are of various wavelength and different energy levels

minimum wavelength will occurs at Gamma rays

and maximum wavelength at Radio waves

the list of increasing order of wavelength is as following

Gamma rays < X rays < Ultraviolet < Visible Light < Infrared Waves < Radio Waves

so least to maximum order is

1. Gamma rays

2. X rays

3 Ultraviolet

4 Visible light

5 Infrared waves

6 Radio waves

5 0
3 years ago
How many meters are in 45 centimeters?
adell [148]

Explanation:

100 CM = 1 m

45 CM = 45 / 100 = 0.45 m

hope it helps:)

6 0
3 years ago
Read 2 more answers
A 4.0 kg circular disk slides in the x- direction on a frictionless horizontal surface with a speed of 5.0 m/s as shown in the a
finlep [7]

Solution :

Let $m_1=m_2=4$ kg

$u_1 = 5$ m/s

Let $v_1$ and $v_2$ are the speeds of the disk $m_1$ and $m_2$  after the collision.

So applying conservation of momentum in the y-direction,

$0=m_1 .v_1_y -m_2 .v_2_y $

$v_1_y = v_2_y$

$v_1 . \sin 60=v_2. \sin 30$

$v_2 = v_1 \times \frac{\sin 60}{\sin 30}$

$v_2=1.732 \times v_1$

Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.

Now applying conservation of momentum in the x-direction,

$m_1.u_1=m_1.v_1_x+m_2.v_2_x$

$u_1=v_1_x+v_2_x$

$5=v_1. \cos 60 + v_2 . \cos 30$

$5=v_1. \cos 60 + 1.732 \times v_1 \cos 30$

$v_1 = 2.50$ m/s

So, $v_2 = 1.732 \times 2.5$

          = 4.33 m/s

Therefore, speed of the disk 2 after collision is 4.33 m/s

5 0
2 years ago
A solid, uniform sphere with a mass of 2.5 kg rolls without slipping down an incline plane starting from rest at a vertical heig
kolezko [41]

Answer:

1/2 m v^2 + 1/2 I ω^2 = m g h       conservation of energy

I = 2/5 m R^2     inertia of solid sphere

1/2 m v^2 + 1/5 m ω^2 R^2 = m g h

1/2 v^2 + 1/5 v^2 = g h

v^2 = 10 g h / 7 = 1.43 * 9.80 * 19 m^2/s^2 = 266 m^2/s^2

v = 16.3 m/s

v = R ω

ω = 16.3 / .6 = 27.2 / sec

8 0
2 years ago
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