Answer:
Step-by-step explanation:
1) BD bisects ∠ABC Given
2) ∠BDA ≅ ∠BDC Given
3) BD ≅ BD Reflexive property
4)Δ BDA ≅ ΔBDC A S A congruent
2) 1.ST ≅ UV Given
2.∠WST ≅ ∠WVU Alternate interior angles, ST //UV and SV transversal
3. ∠WTS≅∠WUV Alternate interior angles, ST//UV and Tu transversal.
4. ΔWST ≅ΔWUV A S A
3) ∠EHF ≅ ∠GHF Given FH bisects ∠EHG
2.∠ FEH ≅∠FGH Given
FH ≅ FH Reflexive property
ΔFEH ≅ΔFGH A A S
