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Fynjy0 [20]
3 years ago
14

PLEASE HELP MATH

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
7 0
I believe C is your answer. 
I hope this helps!
levacccp [35]3 years ago
3 0

\frac{25}{100}  \times 100000 = 25000
so the answer is c. $25,000
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The picture below shows a shaded rectangular region inside a large rectangle.
Pachacha [2.7K]

Answer:

the answer is d

Step-by-step explanation:

8 0
3 years ago
The ratio of two numbers is 8 to 5. The difference in two numbers is 24. What are the numbers?
Varvara68 [4.7K]
Let, the numbers are: 8x, 5x
It is given that, 8x - 5x = 24
3x = 24
x = 24/3
x = 8

So, 8x = 8(8) = 64 
also, 5x = 5(8) = 40

In short, Numbers would be 40 and 64

Hope this helps!
8 0
3 years ago
Help your girl out !!
Usimov [2.4K]

(5x² - 6x + 2)(4x² - 3x)

20x^{4} -15x^{3} -24x^{3} +18x^{2} +8x^{2} -6x

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6 0
3 years ago
Read 2 more answers
You recently took a statistics exam in a large class. The instructor tells the class that the scores were Normally distributed,
Lunna [17]

Answer:

b. the area to the right of 2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.

In this problem:

X = 96, \mu = 72, \sigma = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{96 - 72}{12}

Z = 2

Percentage who did better:

P(Z > 2), which is the area to the right of 2.

5 0
3 years ago
(11p + 3q + 4) + (-5p + 8q)
Fiesta28 [93]
11p + 3q + 4 -5p +8q

6p + 11q + 4 is your answer

hope this helps
8 0
3 years ago
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