Answer:
144 units²
Step-by-step explanation:
The net of the right triangular prism consists of 3 rectangles and 2 equal triangles
Let's solve for the area of each:
✔️Area of rectangle 1 = L*W
L = 11
W = 3
Area of rectangle 1 = 11*3 = 33 units²
✔️Area of rectangle 2 = L*W
L = 11
W = 4
Area of rectangle 2 = 11*4 = 44 units²
✔️Area of rectangle 3 = L*W
L = 11
W = 5
Area of rectangle 3 = 11*5 = 55 units²
✔️Area of the two triangles = 2(½*base*height)
base = 4
height = 3
Area of the two traingles = 2(½*4*3)
= 12 units²
✔️Surface area of the right triangle = area of rectangle 1 + area of rectangle 2 + area of rectangle 3 + area of the two triangles
= 33 + 44 + 55 + 12
= 144 units²
Last one should be less than 3/4
The denominator cannot be zero, so
is not in the domain of 
.
is defined only for 
, and we have
so there is no issue here.
By the same token, we need to have
Taking all the exclusions together, we find the domain of is the set
or equivalently, the interval 
.
