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3 years ago

13

Due at 11:59 P.M. Desperate

1 answer:

pantera1 [17]3 years ago

6 0

Answer: Your answer should be A.

Step-by-step explanation:

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Kaylis [27]

Greatest Common Factor. let's go over that. GCF of 6 and 12 would be 6 because 6 goes into 6, 1 times and 6 goes into 12, 2 times. . and it is the largest. so first you see if the lower number can go directly into the higher number. So 28a^2 b^2 c^2, is made of 14abc× 2abc. so you can say 14abc goes into 28a2b2c2, 2abc times. therefore 14abc is the largest factor.

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3 years ago

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3 years ago

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Andreas93 [3]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

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3 years ago