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Montano1993 [528]
1 year ago
12

Solve the equation. Check the solution. Use a graphing calculator.

Mathematics
1 answer:
sergey [27]1 year ago
8 0

Solution

We solve the equation

\begin{gathered} \frac{3}{x+3}+\frac{6}{x-3}=3 \\  \\ Divide\text{ through by 3} \\  \\ \frac{1}{x+3}+\frac{2}{x-3}=1 \\  \\ Clearing\text{ fraction} \\  \\ x-3+2x+6=x^2-9 \\ 3x+3=x^2-9 \\  \\ x^2-3x-12=0 \end{gathered}

We now solve the quadratic equation

\begin{gathered} x^2-3x-12=0 \\  \\ Using\text{ formula method} \\  \\ x=\frac{3\pm\sqrt{3^2-4(1)(-12)}}{2} \\  \\ x=\frac{3\pm\sqrt{9+48}}{2} \\  \\ x=\frac{3\pm\sqrt{57}}{2} \\  \\ Therefore,\text{ the two answers are given below and corrected to two decimal places} \\  \\ x=5.27 \\ and \\ x=-2.27 \end{gathered}

The graph is given below

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2 years ago
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What is an equation of the line that is perpendicular to −x+2y=4 and passes through the point (−2, 1) ?
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Answer:

y=-2x-3

Step-by-step explanation:

Since our equation is in standard form Ax+By=C we must first manipulate the equation so that we have it in the slope-intercept form such that y=mx+b.  Therefore:

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6 0
3 years ago
The lengths of the sides of a triangle are 3, 4, 5. Can the triangle be a right triangle?
Contact [7]

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Yes it can

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To check wether it's a right angle triangle we need to apply the Pythagoras theorem

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This is correct, so the triangle is a right angle triangle

Answer from Gauthmath

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