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inessss [21]
3 years ago
7

What’s 23y times 4x(simplify)

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

92xy

Step-by-step explanation:

Multiplying 23 by 4 results in 92.

Then 23y times 4x = 92xy

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Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
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Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

5 0
3 years ago
Josh has a rewards card for a movie theater. He receives 15 points for becoming a rewards card holder. He earns 3.5 points for e
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Step-by-step explanation:

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6 0
3 years ago
Please help I found this one a bit confusing ​
Sergio [31]

Answer:

C

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If you look closely.. You can see that one is longer than the other

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3 years ago
GIVING BRAINIEST!!!!!!!!
Sav [38]

Answer:

look at the horizontal line in the picture. the degree measure of any line is 180° given there's a perpendicular ray through that horizontal line it's therfore split into two sides both with angle measure of 90°.

given f is 71° then g can be found knowing that both g and f must add to 90°. 71+g=90. g=19°

now look at f again. f and d are what's known as vertical angles and that means that they're angle measures are congruent. therfore the measure of d is 71° d=71°

Finally to find e we notice that angle d and e form a straight line which means both angles measures must add to 180°. therefore e can be found by computing d+e=180

aunaitituitmg our information we know 71+e=180 then e must equal 109° e=109°

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3 years ago
Describe a situation where it would be better to use a fraction than a decimal or a percentage
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I prefer to use fractions for some irrational numbers.

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