Question

The nth term of the GP is (-1)^n(2)^n.

Answer 1

Answer:

-2, 4 and -8

Explanation:

Given the nth term of a GP expressed as;

$a_n = (-1)^n(2)^n$

When n = 1

$a_1 = (-1)^1(2)^1\\a_1 = -1 * 2\\a_1 = -2$

when n = 2

$a_2 = (-1)^2(2)^2\\a_2 = 1 * 4\\a_2 = 4$

when n = 3

$a_3 = (-1)^3(2)^3\\a_3 = -1 * 8\\a_3 = -8$

Hence the first three terms of the sequence are -2, 4 and -8