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2 years ago

HELPPPO MEEE!!!! is this correct?!!!?! please i really need this

Mathematics

1 answer:

gregori [183]2 years ago

4 0

B 1 solution should be correct but i don’t really know

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The sum of 2x+7 and −x+12 is equal to 14 what is x?

Alekssandra [29.7K]

Answer:-5

Step-by-step explanation:

2x+7-x+12=14

x+19=14

x=-5

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3 years ago

a fish tank is in the shape of a cube the. volume of the fish tank is 64 cubic feet. What is the area of one face of the fish ta

babymother [125]

16 square feet. The cube root of 64 is 4, which is equal to the length of one side. The area of one side is the length times the width, and since this is a cube, the length equals the width, meaning that the side is 4 times 4 which is 16

3 0

2 years ago

Read 2 more answers

(04.03) The graph shows the amount of money paid when purchasing bags of candy at the 2008

alexandr1967 [171]

Answer: yw

y=4.03x+2008

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3 years ago

Jerry has a CD case that contains 4

kvv77 [185]

Answer: $\frac{1}{15}$

Step-by-step explanation:

Given

There are

4 country music CD

1 rock and roll CD

2 rap CD

3 Tejano CD

$\text{Probability that Jerry randomly select a Tejano CD and then a rap CD from his case}=\text{Probability of selecting a Tejano CD}\times \text{Probability of selecting a rap CD}$

$P=\frac{3}{10}\times \frac{2}{9}$

$P=\frac{2}{30}$

$P=\frac{1}{15}$

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2 years ago

One thousand tonnes (1000 t, one t equals 10 cubed kg) of sand contains about a trillion (10 super 12) grains of sand. How many

Phantasy [73]

Answer with Step-by-step explanation:

Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)

Thus we have

1 mole of sand = $6.022\times 10^{23}$ sand particles

Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is

$\frac{6.022\times 10^{23}}{10^{12}}=6.022\times 10^{11}$

Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of $6.022\times 10^{11}$ trillion sand particles is

$Mass=1000\times 6.022\times 10^{11}=6.022\times 10^{14}tonnes$

Part 2)

Since it is given that volume of 1 sand particle is $1.0mm^{3}$ thus the volume of 1 mole of sand is volume of $6.022\times 10^{23}$ sand particles

Thus volume of 1 mole is $V=1.00\times 10^{-18}km^{3}\times 6.022\times 10^{23}=6.022\times 10^{5}km^{3}$

Now since the Area of united states is $A=3.6\times 10^{6}mile^{2}=5.8\times 10^{6}km^{2}$

Thus the depth of the sand pile is

$Depth=\frac{Volume}{Area}=\frac{6.022\times 10^5}{5.8\times 10^6}=0.10387km=103.8meters$

4 0

2 years ago